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Script 方法 (ScriptingOptions)

Generates a Transact-SQL script that can be used to re-create the audit specification as specified by the script options.

命名空间：  Microsoft.SqlServer.Management.Smo
程序集：  Microsoft.SqlServer.Smo（在 Microsoft.SqlServer.Smo.dll 中）

语法

声明
Public Function Script ( _
    scriptingOptions As ScriptingOptions _
) As StringCollection
用法
Dim instance As AuditSpecification
Dim scriptingOptions As ScriptingOptions
Dim returnValue As StringCollection

returnValue = instance.Script(scriptingOptions)

public StringCollection Script(
    ScriptingOptions scriptingOptions
)

public:
virtual StringCollection^ Script(
    ScriptingOptions^ scriptingOptions
) sealed

abstract Script : 
        scriptingOptions:ScriptingOptions -> StringCollection 
override Script : 
        scriptingOptions:ScriptingOptions -> StringCollection 

public final function Script(
    scriptingOptions : ScriptingOptions
) : StringCollection

参数

返回值

类型：System.Collections.Specialized. . :: . .StringCollection
A StringCollection system object value that contains a list of Transact-SQL statements in the script.

实现

IScriptable. . :: . .Script(ScriptingOptions)

注释

生成的脚本可能包含完成脚本输出所必需的未记录的内部过程。

示例

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server
'Reference the AdventureWorks database.
Dim db As Database
db = srv.Databases("AdventureWorks")
'Define a Scripter object and set the required scripting options.
Dim scrp As Scripter
scrp = New Scripter(srv)
scrp.Options.ScriptDrops = False
scrp.Options.WithDependencies = True
'Iterate through the tables in database and script each one. Display the script.
'Note that the StringCollection type needs the System.Collections.Specialized namespace to be included.
Dim tb As Table
Dim smoObjects(1) As Urn
For Each tb In db.Tables
    smoObjects = New Urn(0) {}
    smoObjects(0) = tb.Urn
    If tb.IsSystemObject = False Then
        Dim sc As StringCollection
        sc = scrp.Script(smoObjects)
        Dim st As String
        For Each st In sc
            Console.WriteLine(st)
        Next
    End If
Next