Level 构造函数 (String)

Initializes a new instance of Level using a name.

命名空间:  Microsoft.AnalysisServices
程序集:  Microsoft.AnalysisServices(在 Microsoft.AnalysisServices.dll 中)

语法

声明
Public Sub New ( _
    name As String _
)
用法
Dim name As String

Dim instance As New Level(name)
public Level(
    string name
)
public:
Level(
    String^ name
)
new : 
        name:string -> Level
public function Level(
    name : String
)

参数