能够识别增补字符的字符串操作示例
SQL Server 的这一示例说明能够识别增补字符的字符串处理。 此示例说明五个 Transact-SQL 字符串函数的实现。这些函数提供的字符串操作功能与内置函数的功能相同,但增加了增补字符识别功能,因此既能处理 Unicode 字符串,又能处理增补字符串。 这五个函数分别为 lens()、lefts(), rights(), subs() 和 replace_s(),分别等同于内置函数 LEN(), LEFT(), RIGHT(), SUBSTRING() 和 REPLACE() 字符串函数。
先决条件
若要创建和运行此项目,必须安装下列软件:
SQL Server 或 SQL Server Express。 您可以从 SQL Server Express Documentation and Samples (Express 文档和示例)网站免费获取 SQL Server Express。
SQL Server 开发人员网站提供的 AdventureWorks 数据库
.NET Framework SDK 2.0 或更高版本,或 Microsoft Visual Studio 2005 或更高版本。 您可以免费获取 .NET Framework SDK。
此外,还必须满足以下条件:
您使用的 SQL Server 实例必须已启用 CLR 集成。
若要启用 CLR 集成,请执行以下步骤:
启用 CLR 集成
- 执行以下 Transact-SQL 命令:
sp_configure 'clr enabled', 1
GO
RECONFIGURE
GO
注意 若要启用 CLR,您必须具有 ALTER SETTINGS 服务器级别权限,sysadmin 和 serveradmin 固定服务器角色的成员隐式拥有该权限。
必须在您使用的 SQL Server 实例上安装 AdventureWorks 数据库。
如果您不是要使用的 SQL Server 实例的管理员,则必须让管理员授予您 CreateAssembly 权限,才能完成安装。
生成示例
按照以下说明创建和运行该示例:
打开 Visual Studio 或 .NET Framework 命令提示符。
如有必要,为您的示例创建目录。 对于此示例,我们将使用 C:\MySample。
由于此示例需要签名的程序集,请通过键入以下命令创建一个非对称密钥:
sn -k SampleKey.snk
从命令行提示符执行以下代码之一(具体取决于所选的语言),对示例代码进行编译。
Vbc /reference:C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.Data.dll,C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.dll,C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.Xml.dll /keyfile:Key.snk /target:library SurrogateStringFunction.vb
Csc /reference:C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.Data.dll /reference:C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.dll /reference:C:\Windows\Microsoft.NET\Framework\v2.0.50727\System.XML.dll /keyfile:Key.snk /target:library SurrogateStringFunction.cs
将 Transact-SQL 安装代码复制到一个文件中,并在示例目录中将其另存为 Install.sql。
通过执行以下命令部署程序集和存储过程:
- sqlcmd -E -I -i install.sql -v root = "C:\MySample\"
将 Transact-SQL 测试命令脚本复制到一个文件中,并在示例目录中将其另存为 test.sql。
使用以下命令执行测试脚本:
- sqlcmd -E -I -i test.sql
将 Transact-SQL 清除脚本复制到一个文件中,并在示例目录中将其另存为 cleanup.sql。
使用以下命令执行该脚本:
- sqlcmd -E -I -i cleanup.sql
示例代码
下面是此示例的代码列表。
C#
using System;
using System.Globalization;
using System.Text;
/// <summary>
/// Include several string functions for T-SQL to manipulate surrogate characters.
/// </summary>
public sealed class SurrogateStringFunction
{
/// <summary>
///
/// </summary>
private SurrogateStringFunction()
{}
/// <summary>
/// LenS is equal to T-SQL string function LEN() which returns the number
/// of characters, rather than the number of bytes, of the given string expression.
/// </summary>
/// <param name="value">The input string.</param>
/// <returns>The number of characters in the string.</returns>
public static long LenS(String value)
{
if (value == null) throw new ArgumentNullException("value");
int[] myIndex;
// Remove trailing spaces for situations when the Transact-SQL variable or table column
// uses a fixed length datatype such as nchar(50).
// If the trailing spaces are not excluded, this function will return 50 which is not
// correct or expected.
myIndex = StringInfo.ParseCombiningCharacters(value.TrimEnd());
return (null != myIndex) ? myIndex.Length : 0;
}
/// <summary>
/// SubS only support character expression of T-SQL funciton SUBSTRING()
/// which returns part of a string.
/// </summary>
/// <param name="value">The input string.</param>
/// <param name="start">The position of the first character that will be returned.</param>
/// <param name="length">The number of characters to return.</param>
/// <returns>The string found at the starting position for the specified
/// number characters.</returns>
public static String SubS(String value, int start, int length)
{
if (value == null) throw new ArgumentNullException("value");
if (length < 0)
throw new ArgumentException("Invalid length parameter passed to the substring function.");
// In Transact-SQL, the substring method initializes to 1. So, start should be initialized to at least 1.
// Length also has to be at least 1 or the Transact-SQL result would be an empty string.
if ((start + length) <= 1)
return (String.Empty);
// The 2 if statements below guarentee that the result will match the substring function in
// Transact-SQL which will initialize start to 1 by subtracting from the length.
if (start <= 0 && length > 0)
length--;
if ((start <= 0))
{
length = length + start;
start = 1;
}
int[] myIndex;
myIndex = StringInfo.ParseCombiningCharacters(value);
int NumOfIndexes = (null != myIndex) ? myIndex.Length : 0;
start--;
if ((0 <= start) && (start < NumOfIndexes))
{
int lastIndex = start + length;
// if we are past the last char, then we get the string
// up to the last char
if (lastIndex > (NumOfIndexes - 1))
{
return value.Substring(myIndex[start]);
}
else
{
return value.Substring(myIndex[start], myIndex[lastIndex] - myIndex[start]);
}
}
else
{
return String.Empty;
}
}
//
//
/// <summary>
/// LeftS is equal to T-SQL string function LEFT() which returns the left
/// part of a character string with the specified number of characters.
/// </summary>
/// <param name="value">The input string.</param>
/// <param name="start">The position of the first character that will be returned.</param>
/// <param name="length">The number of characters to return.</param>
/// <returns>The string found at the starting position for n-length.</returns>
public static String LeftS(String value, int length )
{
if (length < 0)
throw new ArgumentException("length must be a positive integer");
return SubS(value, 1, length);
}
// RightS is equal to T-SQL string function RIGHT() which returns the right
// part of a character string with the specified number of characters.
public static String RightS(String value, int length)
{
if (length < 0)
throw new NotSupportedException("length must be a positive integer");
if (value == null) throw new ArgumentNullException("value");
int[] myIndex;
myIndex = StringInfo.ParseCombiningCharacters(value);
int numOfIndexes = (null != myIndex) ? myIndex.Length : 0;
if (numOfIndexes <= length)
return value;
if (length == 0) return String.Empty;
int virtualStartIndex = numOfIndexes - length;
int physicalStartIndex = myIndex[virtualStartIndex];
return value.Substring(physicalStartIndex);
}
//
// ReplaceS is equal to T-SQL string function REPLACE() which replaces all
// occurrences of the second given string expression in the first string expression
// with a third expression.
//
public static String ReplaceS(String value, String replaceValue, String newValue)
{
StringBuilder result = new StringBuilder(value.Length);
int[] myIndex;
int i = 0;
String upperValue = value.ToUpper(CultureInfo.CurrentUICulture);
String upperReplaceValue = replaceValue.ToUpper(CultureInfo.CurrentUICulture);
myIndex = StringInfo.ParseCombiningCharacters(upperValue);
while (i < value.Length)
{
int possibleMatch = upperValue.IndexOf(upperReplaceValue, i);
if (possibleMatch < 0)
{
result.Append(value.Substring(i));
break;
}
else
{
//Ensure we're not matching a partial surrogate
int surrogateIndex = Array.IndexOf<int>(myIndex, possibleMatch);
if (surrogateIndex < 0)
{
//We've matched in the middle of a surrogate, skip this match
//as it is not valid.
int nextStart = possibleMatch + 1;
result.Append(value.Substring(i, nextStart-i));
i = nextStart;
}
else
{
//This is a valid match. Make the substitution.
result.Append(value.Substring(i, possibleMatch - i));
result.Append(newValue);
i = possibleMatch + replaceValue.Length;
}
}
}
return result.ToString();
}
}
Visual Basic
Imports Microsoft.VisualBasic
Imports System
Imports System.Collections
Imports System.Data
Imports System.Diagnostics
Imports System.Globalization
Imports System.Text
''' <summary>
''' Include several string functions for T-SQL to manipulate surrogate characters.
''' </summary>
Public NotInheritable Class SurrogateStringFunction
''' <summary>
''' Empty default constructor
''' </summary>
Private Sub New()
End Sub
''' <summary>
''' LenS is equal to T-SQL string function LEN() which returns the number
''' of characters, rather than the number of bytes, of the given string expression.
''' </summary>
''' <param name="value">The input string.</param>
''' <returns>The number of characters in the string.</returns>
<Microsoft.SqlServer.Server.SqlFunction()> _
Public Shared Function LenS(ByVal value As String) As Long
If value Is Nothing Then
Throw New ArgumentNullException("value")
End If
Dim myIndex() As Integer
' Remove trailing spaces for situations when the Transact-SQL variable or table column
' uses a fixed length datatype such as nchar(50).
' If the trailing spaces are not excluded, this function will return 50 which is not
' correct or expected.
myIndex = StringInfo.ParseCombiningCharacters(value.TrimEnd())
If (myIndex IsNot Nothing) Then
Return myIndex.Length
Else
Return 0
End If
End Function
''' <summary>
''' SubS only support character expression of T-SQL funciton SUBSTRING()
''' which returns part of a string.
''' </summary>
''' <param name="value">The input string.</param>
''' <param name="start">The position of the first character that will be returned.</param>
''' <param name="length">The number of characters to return.</param>
''' <returns>The string found at the starting position for the specified
''' number characters.</returns>
<Microsoft.SqlServer.Server.SqlFunction()> _
Public Shared Function SubS(ByVal value As String, ByVal start As Integer, ByVal length As Integer) As String
If value Is Nothing Then
Throw New ArgumentNullException("value")
End If
If length < 0 Then
Throw New ArgumentException("Invalid length parameter passed to the substring function.")
End If
' In Transact-SQL, the substring method initializes to 1. So, start should be initialized to at least 1.
' Length also has to be at least 1 or the Transact-SQL result would be an empty string.
If start + length <= 1 Then
Return String.Empty
End If
' The 2 if statements below guarentee that the result will match the substring function in
' Transact-SQL which will initialize start to 1 by subtracting from the length.
If start <= 0 AndAlso length > 0 Then
length -= 1
End If
If start <= 0 Then
length = length + start
start = 1
End If
Dim myIndex() As Integer
myIndex = StringInfo.ParseCombiningCharacters(value)
Dim NumOfIndexes As Integer
If (myIndex IsNot Nothing) Then
NumOfIndexes = myIndex.Length
Else
NumOfIndexes = 0
End If
start -= 1
If 0 <= start AndAlso start < NumOfIndexes Then
Dim lastIndex As Integer = start + length
' if we are past the last char, then we get the string
' up to the last char
If lastIndex > NumOfIndexes - 1 Then
Return value.Substring(myIndex(start))
Else
Return value.Substring(myIndex(start), myIndex(lastIndex) - myIndex(start))
End If
Else
Return String.Empty
End If
End Function
''' <summary>
''' LeftS is equal to T-SQL string function LEFT() which returns the left
''' part of a character string with the specified number of characters.
''' </summary>
''' <param name="value">The input string.</param>
''' <param name="length">The number of characters to return.</param>
''' <returns>The string found at the starting position for n-length.</returns>
<Microsoft.SqlServer.Server.SqlFunction()> _
Public Shared Function LeftS(ByVal value As String, ByVal length As Integer) As String
If length < 0 Then
Throw New ArgumentException("Length must be a positive integer")
End If
Return SubS(value, 1, length)
End Function
' RightS is equal to T-SQL string function RIGHT() which returns the right
' part of a character string with the specified number of characters.
<Microsoft.SqlServer.Server.SqlFunction()> _
Public Shared Function RightS(ByVal value As String, ByVal length As Integer) As String
If value Is Nothing Then
Throw New ArgumentNullException("value")
End If
If length < 0 Then
Throw New NotSupportedException("Length must be a positive integer")
End If
Dim myIndex() As Integer
myIndex = StringInfo.ParseCombiningCharacters(value)
Dim NumOfIndexes As Integer
If (myIndex IsNot Nothing) Then
NumOfIndexes = myIndex.Length
Else
NumOfIndexes = 0
End If
If NumOfIndexes <= length Then
Return value
End If
If length = 0 Then
Return String.Empty
End If
Dim virtualStartIndex As Integer = NumOfIndexes - length
Dim physicalStartIndex As Integer = myIndex(virtualStartIndex)
Return value.Substring(physicalStartIndex)
End Function
''' <summary>
''' ReplaceS is equal to T-SQL string function REPLACE() which replaces all
''' occurrences of the second given string expression in the first string expression
''' with a third expression.
''' </summary>
''' <param name="value"></param>
''' <param name="replaceValue"></param>
''' <param name="newValue"></param>
''' <returns></returns>
''' <remarks></remarks>
<Microsoft.SqlServer.Server.SqlFunction()> _
Public Shared Function ReplaceS(ByVal value As String, ByVal replaceValue As String, ByVal newValue As String) As String
Dim result As New StringBuilder(value.Length)
Dim myIndex() As Integer
Dim i As Integer = 0
Dim upperValue As String = value.ToUpper(CultureInfo.CurrentUICulture)
Dim upperReplaceValue As String = replaceValue.ToUpper(CultureInfo.CurrentUICulture)
myIndex = StringInfo.ParseCombiningCharacters(upperValue)
While i < value.Length
Dim possibleMatch As Integer = upperValue.IndexOf(upperReplaceValue, i)
If possibleMatch < 0 Then
result.Append(value.Substring(i))
Exit While
Else
'Ensure we're not matching a partial surrogate
Dim surrogateIndex As Integer = Array.IndexOf(Of Integer)(myIndex, possibleMatch)
If surrogateIndex < 0 Then
'We've matched in the middle of a surrogate, skip this match
'as it is not valid.
Dim nextStart As Integer = possibleMatch + 1
result.Append(value.Substring(i, nextStart - i))
i = nextStart
Else
'This is a valid match. Make the substitution.
result.Append(value.Substring(i, possibleMatch - i))
result.Append(newValue)
i = possibleMatch + replaceValue.Length
End If
End If
End While
Return result.ToString()
End Function
End Class
这是 Transact-SQL 安装脚本 (Install.sql),该脚本在数据库中部署程序集并创建能够识别增补字符的函数。
Use [AdventureWorks]
Go
IF OBJECT_ID('[dbo].[len_s]') IS NOT NULL
DROP FUNCTION [dbo].[len_s];
IF OBJECT_ID('[dbo].[sub_s]') IS NOT NULL
DROP FUNCTION [dbo].[sub_s];
IF OBJECT_ID('[dbo].[left_s]') IS NOT NULL
DROP FUNCTION [dbo].[left_s];
IF OBJECT_ID('[dbo].[right_s]') IS NOT NULL
DROP FUNCTION [dbo].[right_s];
IF OBJECT_ID('[dbo].[replace_s]') IS NOT NULL
DROP FUNCTION [dbo].[replace_s];
GO
IF EXISTS (SELECT [name] FROM sys.assemblies
WHERE [name] = 'SurrogateStringFunction')
DROP ASSEMBLY SurrogateStringFunction;
GO
USE master
GO
IF EXISTS (SELECT * FROM sys.server_principals WHERE [name] = 'ExternalSample_Login')
DROP LOGIN ExternalSample_Login;
GO
IF EXISTS (SELECT * FROM sys.asymmetric_keys WHERE [name] = 'ExternalSample_Key')
DROP ASYMMETRIC KEY ExternalSample_Key;
GO
--Before we register the assembly to SQL Server, we must arrange for the appropriate permissions.
--Assemblies with unsafe or external_access permissions can only be registered and operate correctly
--if either the database trustworthy bit is set or if the assembly is signed with a key,
--that key is registered with SQL Server, a server principal is created from that key,
--and that principal is granted the external access or unsafe assembly permission. We choose
--the latter approach as it is more granular, and therefore safer. You should never
--register an assembly with SQL Server (especially with external_access or unsafe permissions) without
--thoroughly reviewing the source code of the assembly to make sure that its actions
--do not pose an operational or security risk for your site.
DECLARE @SamplesPath nvarchar(1024);
-- You may need to modify the value of the this variable if you have installed the sample someplace other than the default location.
set @SamplesPath = N'C:\MySample\'
EXEC('CREATE ASYMMETRIC KEY ExternalSample_Key FROM EXECUTABLE FILE = ''' + @SamplesPath
+ 'SurrogateStringFunction.dll'';');
CREATE LOGIN ExternalSample_Login FROM ASYMMETRIC KEY ExternalSample_Key
GRANT EXTERNAL ACCESS ASSEMBLY TO ExternalSample_Login;
GO
USE AdventureWorks;
GO
--
-- Create assembly to register class methods for create functions
--
DECLARE @SamplesPath nvarchar(1024);
-- You may need to modify the value of the this variable if you have installed the sample someplace other than the default location.
set @SamplesPath = N'C:\MySample\'
CREATE ASSEMBLY [SurrogateStringFunction]
FROM @SamplesPath + 'SurrogateStringFunction.dll'
WITH PERMISSION_SET = EXTERNAL_ACCESS;
GO
CREATE FUNCTION [dbo].[len_s] (@str nvarchar(4000))
RETURNS bigint
AS EXTERNAL NAME [SurrogateStringFunction].[SurrogateStringFunction].[LenS];
GO
CREATE FUNCTION [dbo].[sub_s](@str nvarchar(4000), @pos int, @cont int)
RETURNS nvarchar(4000)
AS EXTERNAL NAME [SurrogateStringFunction].[SurrogateStringFunction].[SubS];
GO
CREATE FUNCTION [dbo].[left_s](@str nvarchar(4000), @cont int)
RETURNS nvarchar(4000)
AS EXTERNAL NAME [SurrogateStringFunction].[SurrogateStringFunction].[LeftS];
GO
CREATE FUNCTION [dbo].[right_s](@str nvarchar(4000), @cont int)
RETURNS nvarchar(4000)
AS EXTERNAL NAME [SurrogateStringFunction].[SurrogateStringFunction].[RightS];
GO
CREATE FUNCTION [dbo].[replace_s](@str nvarchar(4000), @str1 nvarchar(4000), @str2 nvarchar(4000))
RETURNS nvarchar(4000)
AS EXTERNAL NAME [SurrogateStringFunction].[SurrogateStringFunction].[ReplaceS];
GO
这是 test.sql,该脚本通过执行函数测试该示例。
Use [AdventureWorks]
Go
-- left_s VS Left
print ('***** left_s VS Left *****');
select [dbo].[left_s](N'౷౸123',2);
print(N'Should Return ౷౸');
go
select Left(N'౷౸123',2);
print(N'Will Return ౷');
go
-- right_s VS Right
print ('***** right_s VS Right *****')
select [dbo].[right_s](N'౷౸123',5);
print(N'Should Return ౷౸123');
go
select Right(N'౷౸123',5);
print(N'Will Return ౸123');
go
-- len_s VS Len
print('***** len_s VS Len *****');
select [dbo].[len_s](N'ƾǀǃ12');
print(N'Should Return 5');
go
select Len(N'ƾǀǃ12');
print(N'Will Return 8');
go
-- sub_s VS Substring
print('***** sub_s VS Subscription *****');
select [dbo].[sub_s] (N'♢♣♤♥♦♧♨♩♪♫♬♭♮♯♰♱♲♳',3,5);
print(N'Should Return ♤♥♦♧♨');
go
select substring(N'♢♣♤♥♦♧♨♩♪♫♬♭♮♯♰♱♲♳',3,5);
print(N'Will Return ♣♤');
go
-- replace_s VS Replace
print('***** replace_s VS Replace *****');
select [dbo].[replace_s](N'ᥕᥖᥗᥙᥚᥛᥕᥖᥗᥙᥚᥛ',N'ᥗᥙᥚ',N'ᦼ');
print(N'Should Return ᥖᦼᥛᥕᥖᦼᥛ');
go
select replace(N'ᥕᥖᥗᥙᥚᥛᥕᥖᥗᥙᥚᥛ',N'ᥗᥙᥚ',N'ᦼ');
print(N'Will Return ᦼ');
go
下面的 Transact-SQL 从数据库中删除程序集和函数。
-- Drop assemblies and functions if they exist.
USE [AdventureWorks]
GO
IF OBJECT_ID('[dbo].[len_s]') IS NOT NULL
DROP FUNCTION [dbo].[len_s];
IF OBJECT_ID('[dbo].[sub_s]') IS NOT NULL
DROP FUNCTION [dbo].[sub_s];
IF OBJECT_ID('[dbo].[left_s]') IS NOT NULL
DROP FUNCTION [dbo].[left_s];
IF OBJECT_ID('[dbo].[right_s]') IS NOT NULL
DROP FUNCTION [dbo].[right_s];
IF OBJECT_ID('[dbo].[replace_s]') IS NOT NULL
DROP FUNCTION [dbo].[replace_s];
GO
IF EXISTS (SELECT [name] FROM sys.assemblies
WHERE [name] = 'SurrogateStringFunction')
DROP ASSEMBLY SurrogateStringFunction;
GO
USE master
GO
IF EXISTS (SELECT * FROM sys.server_principals WHERE [name] = 'ExternalSample_Login')
DROP LOGIN ExternalSample_Login;
GO
IF EXISTS (SELECT * FROM sys.asymmetric_keys WHERE [name] = 'ExternalSample_Key')
DROP ASYMMETRIC KEY ExternalSample_Key;
GO
USE [AdventureWorks]
GO