DataType.UserDefinedDataType 方法 (String, String)
Returns an object that represents the specified type with the specified schema.
命名空间: Microsoft.SqlServer.Management.Smo
程序集: Microsoft.SqlServer.Smo(在 Microsoft.SqlServer.Smo.dll 中)
语法
声明
Public Shared Function UserDefinedDataType ( _
type As String, _
schema As String _
) As DataType
用法
Dim type As String
Dim schema As String
Dim returnValue As DataType
returnValue = DataType.UserDefinedDataType(type, _
schema)
public static DataType UserDefinedDataType(
string type,
string schema
)
public:
static DataType^ UserDefinedDataType(
String^ type,
String^ schema
)
static member UserDefinedDataType :
type:string *
schema:string -> DataType
public static function UserDefinedDataType(
type : String,
schema : String
) : DataType
参数
- type
类型:System.String
A String value that specifies the type.
- schema
类型:System.String
A String value that specifies the schema.
返回值
类型:Microsoft.SqlServer.Management.Smo.DataType
A DataType object value.
示例
The following code example shows how to create a table whose columns depend on a pair of user-defined data types.
C#
Server srv = new Server("(local)");
Database db = srv.Databases("AdventureWorks2012");
Schema schema1 = new Schema(db, "schema1");
schema1.Create();
UserDefinedDataType uddt = new UserDefinedDataType(db, "uddt");
uddt.SystemType = "int";
uddt.Create();
UserDefinedDataType uddt1 = new UserDefinedDataType(db, "uddt1");
uddt1.Schema = "schema1";
uddt1.SystemType = "int";
uddt1.Create();
UserDefinedDataType uddt2 = new UserDefinedDataType(db, "uddt2", "schema1");
uddt2.SystemType = "nvarchar";
uddt2.Length = 90;
uddt2.Create();
Table table = new Table(db, "mytable");
table.Columns.Add((new Column(table, "c1", Microsoft.SqlServer.Management.Smo.DataType.NVarChar(100))));
table.Columns.Add((new Column(table, "c2", Microsoft.SqlServer.Management.Smo.DataType.UserDefinedDataType("uddt"))));
Column c = new Column(table, "c3");
c.DataType = new DataType(SqlDataType.UserDefinedDataType, "uddt1", "schema1");
table.Columns.Add(c);
Column c1 = new Column(table, "c4");
c1.DataType = new DataType(uddt);
table.Columns.Add(c1);
DataType dt = new DataType(uddt2);
Column c2 = new Column(table, "c5");
c2.DataType = dt;
table.Columns.Add(c2);
table.Create();
PowerShell
#Connect to the default, local server and open the AdventureWorks2012 database
$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = $srv.Databases.Item("AdventureWorks2012")
#Create the schema and a pair of user-defined data types
$schema1 = new-object Microsoft.SqlServer.Management.Smo.Schema($db, "schema1")
$schema1.Create()
$uddt = new-object Microsoft.SqlServer.Management.Smo.UserDefinedDataType($db, "uddt")
$uddt.SystemType = "int"
$uddt.Create()
$uddt1 = new-object Microsoft.SqlServer.Management.Smo.UserDefinedDataType($db, "uddt1")
$uddt1.schema = "schema1"
$uddt1.SystemType = "int"
$uddt1.Create()
$uddt2 = new-object Microsoft.SqlServer.Management.Smo.UserDefinedDataType($db, "uddt2")
$uddt2.SystemType = "nvarchar"
$uddt2.Length = 90
$uddt2.Create()
#Define the table columns
$table = new-object Microsoft.SqlServer.Management.Smo.Table($db, "mytable")
$c1 = new-object Microsoft.SqlServer.Management.Smo.Column($table, "c1", [Microsoft.SqlServer.Management.Smo.DataType]::NVarChar(100))
$c2 = new-object Microsoft.SqlServer.Management.Smo.Column($table, "c2", [Microsoft.SqlServer.Management.Smo.DataType]::UserDefinedDataType("uddt"))
$c3 = new-object Microsoft.SqlServer.Management.Smo.Column($table, "c3")
$c3.DataType = new-object Microsoft.SqlServer.Management.Smo.DataType([Microsoft.SqlServer.Management.Smo.SqlDataType]::UserDefinedDataType, "uddt1", "schema1")
$c4 = new-object Microsoft.SqlServer.Management.Smo.Column($table, "c4")
$c4.DataType = new-object Microsoft.SqlServer.Management.Smo.DataType($uddt)
$dt = new-object Microsoft.SqlServer.Management.Smo.DataType($uddt2)
$c5 = new-object Microsoft.SqlServer.Management.Smo.Column($table, "c5")
$c5.DataType = $dt
#Add the columns and create the table
$table.Columns.Add($c1)
$table.Columns.Add($c2)
$table.Columns.Add($c3)
$table.Columns.Add($c4)
$table.Columns.Add($c5)
$table.Create()