Table.Grant 方法 (ObjectPermissionSet, String, array<String )

项目
04/26/2013

Grants access to the specified permission on the specified columns for the specified grantee on the specified columns on the table.

命名空间： Microsoft.SqlServer.Management.Smo
程序集： Microsoft.SqlServer.Smo（在 Microsoft.SqlServer.Smo.dll 中）

语法

声明
Public Sub Grant ( _
    permission As ObjectPermissionSet, _
    granteeName As String, _
    columnNames As String() _
)
用法
Dim instance As Table 
Dim permission As ObjectPermissionSet 
Dim granteeName As String 
Dim columnNames As String()

instance.Grant(permission, granteeName, _
    columnNames)

public void Grant(
    ObjectPermissionSet permission,
    string granteeName,
    string[] columnNames
)

public:
virtual void Grant(
    ObjectPermissionSet^ permission, 
    String^ granteeName, 
    array<String^>^ columnNames
) sealed

abstract Grant : 
        permission:ObjectPermissionSet * 
        granteeName:string * 
        columnNames:string[] -> unit  
override Grant : 
        permission:ObjectPermissionSet * 
        granteeName:string * 
        columnNames:string[] -> unit

public final function Grant(
    permission : ObjectPermissionSet, 
    granteeName : String, 
    columnNames : String[]
)

参数

permission
类型：Microsoft.SqlServer.Management.Smo.ObjectPermissionSet
An ObjectPermissionSet object that specifies the set of permissions.

granteeName
类型：System.String
A String value that specifies the grantee to be granted access to the set of permissions.

columnNames
类型：array<System.String[]
A String array value that specifies the list of columns to which the set of permissions is granted.

实现

IColumnPermission.Grant(ObjectPermissionSet, String, array<String[])

示例

The following code example shows how to grant a grantee account permission to select table elements of the second table column. The grantee account is a placeholder for any defined user accounts.

The following database schema is used for this snippet.

//CREATE DATABASE MYTESTDB;
//GO

//USE MYTESTDB;
//GO

//CREATE TABLE TABLE1(
//    id int,
//    name varchar(32)
//);
//GO

Server srv = new Server("(local)");
Database db = srv.Databases["MYTESTDB"];

Table tb = db.Tables[0];
String[] col = new String[1];
col[0] = tb.Columns[0].Name;
col[1] = tb.Columns[1].Name

ObjectPermissionSet objPermissionSet = new ObjectPermissionSet(ObjectPermission.Select);
objPermissionSet.Select = true;
tb.Grant(objPermissionSet, grantee, col[]);

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("MYTESTDB")
$tb = $db.Tables[0]
$col = @($tb.Columns[0].Name, $tb.Columns[1].Name)

$objPermissionSet = new-object Microsoft.SqlServer.Management.Smo.ObjectPermissionSet([Microsoft.SqlServer.Management.Smo.ObjectPermission]::Select)
$objPermissionSet.Select = $TRUE
$tb.Grant($objPermissionSet, grantee, $col)