list::remove
Erases elements in a list that match a specified value.
void remove(
const Type& _Val
);
Parameters
- _Val
The value which, if held by an element, will result in that element's removal from the list.
Remarks
The order of the elements remaining is not affected.
Example
// list_remove.cpp
// compile with: /EHsc
#include <list>
#include <iostream>
int main( )
{
using namespace std;
list <int> c1;
list <int>::iterator c1_Iter, c2_Iter;
c1.push_back( 5 );
c1.push_back( 100 );
c1.push_back( 5 );
c1.push_back( 200 );
c1.push_back( 5 );
c1.push_back( 300 );
cout << "The initial list is c1 =";
for ( c1_Iter = c1.begin( ); c1_Iter != c1.end( ); c1_Iter++ )
cout << " " << *c1_Iter;
cout << endl;
list <int> c2 = c1;
c2.remove( 5 );
cout << "After removing elements with value 5, the list becomes c2 =";
for ( c2_Iter = c2.begin( ); c2_Iter != c2.end( ); c2_Iter++ )
cout << " " << *c2_Iter;
cout << endl;
}
The initial list is c1 = 5 100 5 200 5 300
After removing elements with value 5, the list becomes c2 = 100 200 300
Requirements
Header: <list>
Namespace: std