^ 运算符（C# 参考）
二元 ^ 运算符是为整型和 bool 类型预定义的。对于整型，^ 将计算操作数的按位“异或”。对于 bool 操作数，^ 将计算操作数的逻辑“异或”；也就是说，当且仅当只有一个操作数为 true 时，结果才为 true。
备注
用户定义的类型可重载 ^ 运算符（请参见运算符）。在枚举时通常允许整型运算。
示例
class XOR
{
static void Main()
{
// Logical exclusive-OR
// When one operand is true and the other is false, exclusive-OR
// returns True.
Console.WriteLine(true ^ false);
// When both operands are false, exclusive-OR returns False.
Console.WriteLine(false ^ false);
// When both operands are true, exclusive-OR returns False.
Console.WriteLine(true ^ true);
// Bitwise exclusive-OR
// Bitwise exclusive-OR of 0 and 1 returns 1.
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0x0 ^ 0x1, 2));
// Bitwise exclusive-OR of 0 and 0 returns 0.
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0x0 ^ 0x0, 2));
// Bitwise exclusive-OR of 1 and 1 returns 0.
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0x1 ^ 0x1, 2));
// With more than one digit, perform the exclusive-OR column by column.
// 10
// 11
// --
// 01
// Bitwise exclusive-OR of 10 (2) and 11 (3) returns 01 (1).
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0x2 ^ 0x3, 2));
// Bitwise exclusive-OR of 101 (5) and 011 (3) returns 110 (6).
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0x5 ^ 0x3, 2));
// Bitwise exclusive-OR of 1111 (decimal 15, hexadecimal F) and 0101 (5)
// returns 1010 (decimal 10, hexadecimal A).
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0xf ^ 0x5, 2));
// Finally, bitwise exclusive-OR of 11111000 (decimal 248, hexadecimal F8)
// and 00111111 (decimal 63, hexadecimal 3F) returns 11000111, which is
// 199 in decimal, C7 in hexadecimal.
Console.WriteLine("Bitwise result: {0}", Convert.ToString(0xf8 ^ 0x3f, 2));
}
}
/*
Output:
True
False
False
Bitwise result: 1
Bitwise result: 0
Bitwise result: 0
Bitwise result: 1
Bitwise result: 110
Bitwise result: 1010
Bitwise result: 11000111
*/
在前面的示例中，0xf8 ^ 0x3f 的计算对以下两个二进制值（分别对应于十六进制值 F8 和 3F）执行按位“异或”运算：
1111 1000
0011 1111
“异或”运算的结果是 1100 0111，即十六进制值 C7。