GrammarBuilder.DebugShowPhrases 屬性

定義

命名空間:

System.Speech.Recognition

組件:

System.Speech.dll

套件:

System.Speech v11.0.0-preview.3.26207.106

來源:

GrammarBuilder.cs

會得到一個字串，顯示文法 GrammarBuilder的內容與結構。

public:
 property System::String ^ DebugShowPhrases { System::String ^ get(); };

public string DebugShowPhrases { get; }

member this.DebugShowPhrases : string

Public ReadOnly Property DebugShowPhrases As String

屬性值

String

目前的內容與結構 GrammarBuilder。

範例

以下範例建立一種語音辨識文法，用於點最多四種配料的披薩。 它會在建立文法之前，先將 的 GrammarBuilder 狀態寫入主控台。 此方法產生以下輸出：

• GrammarBuilder status: I would like a [cheese,mushroom,tomato,onion,anchovy,chic ken,pepperoni] and [cheese,mushroom,tomato,onion,anchovy,chicken,pepperoni] pizza

private static Grammar CreatePizzaGrammar()
{

  // Create a Choices object with alternatives for toppings.
  Choices toppings = new Choices(new string[] {
    "cheese", "mushroom", "tomato", "onion",
    "anchovy", "chicken", "pepperoni"});

  // Create a GrammarBuilder and append the Choices object.
  GrammarBuilder andToppings = new GrammarBuilder("and", 0, 1);
  andToppings.Append(toppings);

  // Construct the phrase.
  GrammarBuilder gb = new GrammarBuilder("I would like a", 0, 1);
  gb.Append(toppings);
  gb.Append(new GrammarBuilder(andToppings, 0, 3));
  gb.Append("pizza");

  // Write the contents and structure of the GrammarBuilder to the console.
  Console.WriteLine("Grammar content and structure: {0}", gb.DebugShowPhrases);

  // Create the Grammar from the GrammarBuilder.
  Grammar grammar = new Grammar(gb);
  grammar.Name = "Pizza Order";

  return grammar;
}