MenuWithTitle.GetLabel Property
Definition
Important
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getLabel
Represents the following attribute in the schema: getLabel
[DocumentFormat.OpenXml.SchemaAttr(0, "getLabel")]
public DocumentFormat.OpenXml.StringValue GetLabel { get; set; }public DocumentFormat.OpenXml.StringValue GetLabel { get; set; }[DocumentFormat.OpenXml.SchemaAttr(0, "getLabel")]
public DocumentFormat.OpenXml.StringValue? GetLabel { get; set; }[DocumentFormat.OpenXml.SchemaAttr("getLabel")]
public DocumentFormat.OpenXml.StringValue? GetLabel { get; set; }public DocumentFormat.OpenXml.StringValue? GetLabel { get; set; }member this.GetLabel : DocumentFormat.OpenXml.StringValue with get, set[<DocumentFormat.OpenXml.SchemaAttr(0, "getLabel")>]
member this.GetLabel : DocumentFormat.OpenXml.StringValue with get, set[<DocumentFormat.OpenXml.SchemaAttr("getLabel")>]
member this.GetLabel : DocumentFormat.OpenXml.StringValue with get, setPublic Property GetLabel As StringValueProperty Value
- Attributes