MenuWithTitle.GetShowLabel Property
Definition
Important
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getShowLabel
Represents the following attribute in the schema: getShowLabel
[DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")]
public DocumentFormat.OpenXml.StringValue GetShowLabel { get; set; }public DocumentFormat.OpenXml.StringValue GetShowLabel { get; set; }[DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")]
public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }[DocumentFormat.OpenXml.SchemaAttr("getShowLabel")]
public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, set[<DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")>]
member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, set[<DocumentFormat.OpenXml.SchemaAttr("getShowLabel")>]
member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, setPublic Property GetShowLabel As StringValueProperty Value
- Attributes