RelationalDatabaseCreatorDependencies.Inequality 運算子

參考

定義

命名空間:: Microsoft.EntityFrameworkCore.Storage

組件:: Microsoft.EntityFrameworkCore.Relational.dll

套件:: Microsoft.EntityFrameworkCore.Relational v6.0.0

套件:: Microsoft.EntityFrameworkCore.Relational v7.0.0

套件:: Microsoft.EntityFrameworkCore.Relational v8.0.0

套件:: Microsoft.EntityFrameworkCore.Relational v9.0.0

來源:: RelationalDatabaseCreatorDependencies.cs

來源:: RelationalDatabaseCreatorDependencies.cs

來源:: RelationalDatabaseCreatorDependencies.cs

來源:: RelationalDatabaseCreatorDependencies.cs

重要

部分資訊涉及發行前產品，在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊，不做任何明確或隱含的瑕疵擔保。

public static bool operator != (Microsoft.EntityFrameworkCore.Storage.RelationalDatabaseCreatorDependencies? left, Microsoft.EntityFrameworkCore.Storage.RelationalDatabaseCreatorDependencies? right);

static member op_Inequality : Microsoft.EntityFrameworkCore.Storage.RelationalDatabaseCreatorDependencies * Microsoft.EntityFrameworkCore.Storage.RelationalDatabaseCreatorDependencies -> bool

Public Shared Operator != (left As RelationalDatabaseCreatorDependencies, right As RelationalDatabaseCreatorDependencies) As Boolean

參數

left: RelationalDatabaseCreatorDependencies

right: RelationalDatabaseCreatorDependencies

傳回

Boolean

適用於