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JulianCalendar.AddYears(DateTime, Int32) 方法

定義

傳回與指定 DateTime 相差指定年數的 DateTime

public:
 override DateTime AddYears(DateTime time, int years);
public override DateTime AddYears (DateTime time, int years);
override this.AddYears : DateTime * int -> DateTime
Public Overrides Function AddYears (time As DateTime, years As Integer) As DateTime

參數

time
DateTime

要將年份加入的 DateTime

years
Int32

要新增的年數。

傳回

DateTime,由將指定的年數加入指定的 DateTime 所產生。

例外狀況

產生的 DateTime 在支援的範圍之外。

範例

下列程式代碼範例會根據 Julian 行事曆顯示 的數位 DateTime 件值。

using namespace System;
using namespace System::Globalization;
void DisplayValues( Calendar^ myCal, DateTime myDT )
{
   Console::WriteLine( "   Era:        {0}", myCal->GetEra( myDT ) );
   Console::WriteLine( "   Year:       {0}", myCal->GetYear( myDT ) );
   Console::WriteLine( "   Month:      {0}", myCal->GetMonth( myDT ) );
   Console::WriteLine( "   DayOfYear:  {0}", myCal->GetDayOfYear( myDT ) );
   Console::WriteLine( "   DayOfMonth: {0}", myCal->GetDayOfMonth( myDT ) );
   Console::WriteLine( "   DayOfWeek:  {0}", myCal->GetDayOfWeek( myDT ) );
   Console::WriteLine();
}

int main()
{
   
   // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
   DateTime myDT = DateTime(2002,4,3,gcnew GregorianCalendar);
   
   // Creates an instance of the JulianCalendar.
   JulianCalendar^ myCal = gcnew JulianCalendar;
   
   // Displays the values of the DateTime.
   Console::WriteLine( "April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:" );
   DisplayValues( myCal, myDT );
   
   // Adds two years and ten months.
   myDT = myCal->AddYears( myDT, 2 );
   myDT = myCal->AddMonths( myDT, 10 );
   
   // Displays the values of the DateTime.
   Console::WriteLine( "After adding two years and ten months:" );
   DisplayValues( myCal, myDT );
}

/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
   Era:        1
   Year:       2002
   Month:      3
   DayOfYear:  80
   DayOfMonth: 21
   DayOfWeek:  Wednesday

After adding two years and ten months:
   Era:        1
   Year:       2005
   Month:      1
   DayOfYear:  21
   DayOfMonth: 21
   DayOfWeek:  Thursday

*/
using System;
using System.Globalization;

public class SamplesJulianCalendar  {

   public static void Main()  {

      // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      DateTime myDT = new DateTime( 2002, 4, 3, new GregorianCalendar() );

      // Creates an instance of the JulianCalendar.
      JulianCalendar myCal = new JulianCalendar();

      // Displays the values of the DateTime.
      Console.WriteLine( "April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:" );
      DisplayValues( myCal, myDT );

      // Adds two years and ten months.
      myDT = myCal.AddYears( myDT, 2 );
      myDT = myCal.AddMonths( myDT, 10 );

      // Displays the values of the DateTime.
      Console.WriteLine( "After adding two years and ten months:" );
      DisplayValues( myCal, myDT );
   }

   public static void DisplayValues( Calendar myCal, DateTime myDT )  {
      Console.WriteLine( "   Era:        {0}", myCal.GetEra( myDT ) );
      Console.WriteLine( "   Year:       {0}", myCal.GetYear( myDT ) );
      Console.WriteLine( "   Month:      {0}", myCal.GetMonth( myDT ) );
      Console.WriteLine( "   DayOfYear:  {0}", myCal.GetDayOfYear( myDT ) );
      Console.WriteLine( "   DayOfMonth: {0}", myCal.GetDayOfMonth( myDT ) );
      Console.WriteLine( "   DayOfWeek:  {0}", myCal.GetDayOfWeek( myDT ) );
      Console.WriteLine();
   }
}

/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
   Era:        1
   Year:       2002
   Month:      3
   DayOfYear:  80
   DayOfMonth: 21
   DayOfWeek:  Wednesday

After adding two years and ten months:
   Era:        1
   Year:       2005
   Month:      1
   DayOfYear:  21
   DayOfMonth: 21
   DayOfWeek:  Thursday

*/
Imports System.Globalization


Public Class SamplesJulianCalendar   

   Public Shared Sub Main()

      ' Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      Dim myDT As New DateTime(2002, 4, 3, New GregorianCalendar())

      ' Creates an instance of the JulianCalendar.
      Dim myCal As New JulianCalendar()

      ' Displays the values of the DateTime.
      Console.WriteLine("April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:")
      DisplayValues(myCal, myDT)

      ' Adds two years and ten months.
      myDT = myCal.AddYears(myDT, 2)
      myDT = myCal.AddMonths(myDT, 10)

      ' Displays the values of the DateTime.
      Console.WriteLine("After adding two years and ten months:")
      DisplayValues(myCal, myDT)

   End Sub

   Public Shared Sub DisplayValues(myCal As Calendar, myDT As DateTime)
      Console.WriteLine("   Era:        {0}", myCal.GetEra(myDT))
      Console.WriteLine("   Year:       {0}", myCal.GetYear(myDT))
      Console.WriteLine("   Month:      {0}", myCal.GetMonth(myDT))
      Console.WriteLine("   DayOfYear:  {0}", myCal.GetDayOfYear(myDT))
      Console.WriteLine("   DayOfMonth: {0}", myCal.GetDayOfMonth(myDT))
      Console.WriteLine("   DayOfWeek:  {0}", myCal.GetDayOfWeek(myDT))
      Console.WriteLine()
   End Sub

End Class


'This code produces the following output.
'
'April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
'   Era:        1
'   Year:       2002
'   Month:      3
'   DayOfYear:  80
'   DayOfMonth: 21
'   DayOfWeek:  Wednesday
'
'After adding two years and ten months:
'   Era:        1
'   Year:       2005
'   Month:      1
'   DayOfYear:  21
'   DayOfMonth: 21
'   DayOfWeek:  Thursday

備註

如果產生的日期不是所產生年份之月份的有效日期,則產生的日期部分 DateTime 會受到影響。 它變更為結果年份結果月份的最後一個有效日。 產生的 DateTime 月份部分會維持與指定的 DateTime相同。 此實作僅支援目前的紀元。 因此, ArgumentException 如果產生的年份超出指定 DateTime之 的紀元,則會擲回 。 結果 DateTime 的當日時間部分會維持與指定的 DateTime相同。

例如,2 月有 28 天,但當閏年有 29 天時除外。 如果指定的日期是閏年 2 月的第 29 天,而的值 years 是 1,則產生的日期是下一年 2 月的第 28 天。

如果 years 為負數,則產生的 DateTime 值早於指定的 DateTime

KindDateTime回值的 屬性一律等於 DateTimeKind.Unspecified。 您可以呼叫 DateTime.SpecifyKind 方法來保留 Kind 參數的 time 屬性,如下列範例所示。

returnTime = DateTime.SpecifyKind(cal.AddYears(time, years), time.Kind);
returnTime = DateTime.SpecifyKind(cal.AddYears(time, years), time.Kind)

適用於

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