Tensor.Dot<T> 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
計算包含數位的兩個張量點乘積。
public:
generic <typename T>
where T : System::Numerics::IAdditionOperators<T, T, T>, System::Numerics::IAdditiveIdentity<T, T>, System::Numerics::IMultiplicativeIdentity<T, T>, System::Numerics::IMultiplyOperators<T, T, T> static T Dot(System::Numerics::Tensors::ReadOnlyTensorSpan<T> % x, System::Numerics::Tensors::ReadOnlyTensorSpan<T> % y);
public static T Dot<T>(in System.Numerics.Tensors.ReadOnlyTensorSpan<T> x, in System.Numerics.Tensors.ReadOnlyTensorSpan<T> y) where T : System.Numerics.IAdditionOperators<T,T,T>, System.Numerics.IAdditiveIdentity<T,T>, System.Numerics.IMultiplicativeIdentity<T,T>, System.Numerics.IMultiplyOperators<T,T,T>;
static member Dot : ReadOnlyTensorSpan * ReadOnlyTensorSpan -> 'T (requires 'T :> System.Numerics.IAdditionOperators<'T, 'T, 'T> and 'T :> System.Numerics.IAdditiveIdentity<'T, 'T> and 'T :> System.Numerics.IMultiplicativeIdentity<'T, 'T> and 'T :> System.Numerics.IMultiplyOperators<'T, 'T, 'T>)
Public Function Dot(Of T As {IAdditionOperators(Of T, T, T), IAdditiveIdentity(Of T, T), IMultiplicativeIdentity(Of T, T), IMultiplyOperators(Of T, T, T)}) (ByRef x As ReadOnlyTensorSpan(Of T), ByRef y As ReadOnlyTensorSpan(Of T)) As T
類型參數
- T
參數
傳回
T