Vector64<T>.BitwiseAnd(Vector64<T>, Vector64<T>) 運算子

定義

計算兩個向量的位和 。

public:
 static System::Runtime::Intrinsics::Vector64<T> operator &(System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> operator & (System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right);
static member ( &&& ) : System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> -> System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)>
static member ( &&& ) : System.Runtime.Intrinsics.Vector64<'T> * System.Runtime.Intrinsics.Vector64<'T> -> System.Runtime.Intrinsics.Vector64<'T>
Public Shared Operator And (left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)

參數

left
Vector64<T>

與 位和 的 right 向量。

right
Vector64<T>

與 位和 的 left 向量。

傳回

和 的位和 leftright

例外狀況

不支援向 T 量 () 的類型。

適用於