DiscoveryMessageSequence.Inequality 運算子

定義

命名空間:

System.ServiceModel.Discovery

組件:

System.ServiceModel.Discovery.dll

判斷兩個指定的 DiscoveryMessageSequence 執行個體是否不相等。

public:
 static bool operator !=(System::ServiceModel::Discovery::DiscoveryMessageSequence ^ messageSequence1, System::ServiceModel::Discovery::DiscoveryMessageSequence ^ messageSequence2);

public static bool operator != (System.ServiceModel.Discovery.DiscoveryMessageSequence messageSequence1, System.ServiceModel.Discovery.DiscoveryMessageSequence messageSequence2);

static member op_Inequality : System.ServiceModel.Discovery.DiscoveryMessageSequence * System.ServiceModel.Discovery.DiscoveryMessageSequence -> bool

Public Shared Operator != (messageSequence1 As DiscoveryMessageSequence, messageSequence2 As DiscoveryMessageSequence) As Boolean

參數

messageSequence1

DiscoveryMessageSequence

探索訊息序列。

messageSequence2

DiscoveryMessageSequence

探索訊息序列。

傳回

Boolean

如果兩個探索訊息序列的執行個體不相等，則為 true，否則為 false。