Point4D.Multiply(Point4D, Matrix3D) 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
public:
static System::Windows::Media::Media3D::Point4D Multiply(System::Windows::Media::Media3D::Point4D point, System::Windows::Media::Media3D::Matrix3D matrix);
public static System.Windows.Media.Media3D.Point4D Multiply (System.Windows.Media.Media3D.Point4D point, System.Windows.Media.Media3D.Matrix3D matrix);
static member Multiply : System.Windows.Media.Media3D.Point4D * System.Windows.Media.Media3D.Matrix3D -> System.Windows.Media.Media3D.Point4D
Public Shared Function Multiply (point As Point4D, matrix As Matrix3D) As Point4D
參數
傳回
傳回轉換 point
和 matrix
的結果。
範例
下列範例示範如何將 結構乘 Point4D 以 Matrix3D 結構。
// Multiplies a Point4D by a Matrix.
// Returns a Point4D.
Point4D point1 = new Point4D(10, 5, 1, 4);
Point4D pointResult = new Point4D();
Matrix3D matrix1 = new Matrix3D(10, 10, 10, 0, 20, 20, 20, 0, 30, 30, 30, 0, 5, 10, 15, 1);
pointResult = Point4D.Multiply(point1, matrix1);
// pointResult is equal to (250, 270, 290, 4)
// Displaying Results
resultType = "Point4D";
syntaxString = "pointResult = Point4D.Multiply(point1, matrix1);";
operationString = "Multiplying a Point4D by a Matrix3D";
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString);
' Multiplies a Point4D by a Matrix.
' Returns a Point4D.
Dim point1 As New Point4D(10, 5, 1, 4)
Dim pointResult As New Point4D()
Dim matrix1 As New Matrix3D(10, 10, 10, 0, 20, 20, 20, 0, 30, 30, 30, 0, 5, 10, 15, 1)
pointResult = Point4D.Multiply(point1, matrix1)
' pointResult is equal to (250, 270, 290, 4)
' Displaying Results
resultType = "Point4D"
syntaxString = "pointResult = Point4D.Multiply(point1, matrix1)"
operationString = "Multiplying a Point4D by a Matrix3D"
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString)