共用方式為


Size3D.Equality(Size3D, Size3D) 運算子

定義

比較兩個 Size3D 結構是否相等。 兩個 Size3D 結構的 XYZ 屬性若相同,就表示兩個結構相等。

public:
 static bool operator ==(System::Windows::Media::Media3D::Size3D size1, System::Windows::Media::Media3D::Size3D size2);
public static bool operator == (System.Windows.Media.Media3D.Size3D size1, System.Windows.Media.Media3D.Size3D size2);
static member ( = ) : System.Windows.Media.Media3D.Size3D * System.Windows.Media.Media3D.Size3D -> bool
Public Shared Operator == (size1 As Size3D, size2 As Size3D) As Boolean

參數

size1
Size3D

要比較的第一個 Size3D 結構。

size2
Size3D

要比較的第二個 Size3D 結構。

傳回

如果 size1size2XYZ 元件都相等則為 true,否則為 false

範例

下列範例示範如何使用多載相等運算子來檢查兩 Size3D 個結構是否相等。

// Checks if two Size3D structures are equal using the overloaded == operator. 
// Returns a Boolean.

// Declaring Size3D structure without initializing x,y,z values
Size3D size1 = new Size3D();

// Declaring Size3D structure and initializing x,y,z values
Size3D size2 = new Size3D(5, 10, 15);
Boolean areEqual;

// Assigning values to size1
size1.X = 2;
size1.Y = 4;
size1.Z = 6;

// Checking for equality
areEqual = size1 == size2;

// areEqual is False

// Displaying Results
syntaxString = " areEqual = size1 == size2;";
resultType = "Boolean";
operationString = "Checking if two Size3D structures are equal";
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString);
' Checks if two Size3D structures are equal using the overloaded == operator. 
' Returns a Boolean.

' Declaring Size3D structure without initializing x,y,z values
Dim size1 As New Size3D()

' Declaring Size3D structure and initializing x,y,z values
Dim size2 As New Size3D(5, 10, 15)
Dim areEqual As Boolean

' Assigning values to size1
size1.X = 2
size1.Y = 4
size1.Z = 6

' Checking for equality
areEqual = size1 = size2

' areEqual is False

' Displaying Results
syntaxString = " areEqual = size1 == size2"
resultType = "Boolean"
operationString = "Checking if two Size3D structures are equal"
ShowResults(areEqual.ToString(), syntaxString, resultType, operationString)

備註

由於在算數運算上執行算數運算時,值可能會失去精確度,因此 Double 邏輯上相等的兩 Size3D 個實例之間的比較可能會失敗。

適用於

另請參閱