共用方式為


UITouch.Type 屬性

定義

[ObjCRuntime.Introduced(ObjCRuntime.PlatformName.iOS, 9, 0, ObjCRuntime.PlatformArchitecture.All, null)]
public virtual UIKit.UITouchType Type { [Foundation.Export("type")] [ObjCRuntime.Introduced(ObjCRuntime.PlatformName.iOS, 9, 0, ObjCRuntime.PlatformArchitecture.All, null)] get; }
member this.Type : UIKit.UITouchType

屬性值

屬性

適用於