System.Object.Equals 方法
本文提供此 API 參考文件的補充備註。
本文與 Object.Equals(Object) 方法有關。
目前實例與 obj
參數之間的比較類型取決於目前實例是參考型別還是實值型別。
如果目前的實例是參考型別,則 Equals(Object) 方法會測試參考是否相等,而對方法的呼叫 Equals(Object) 相當於對 方法的 ReferenceEquals 呼叫。 參考相等表示比較的物件變數會參考相同的物件。 下列範例說明這類比較的結果。 它會定義類別
Person
,這是參考型別,並呼叫Person
類別建構函式來具現化兩個新Person
物件,person1a
以及person2
具有相同值的 。 它也會指定person1a
給另一個物件變數person1b
。 如範例的輸出所示,person1a
和person1b
相等,因為它們參考相同的物件。 不過,person1a
和person2
不相等,雖然它們具有相同的值。using System; // Define a reference type that does not override Equals. public class Person { private string personName; public Person(string name) { this.personName = name; } public override string ToString() { return this.personName; } } public class Example1 { public static void Main() { Person person1a = new Person("John"); Person person1b = person1a; Person person2 = new Person(person1a.ToString()); Console.WriteLine("Calling Equals:"); Console.WriteLine("person1a and person1b: {0}", person1a.Equals(person1b)); Console.WriteLine("person1a and person2: {0}", person1a.Equals(person2)); Console.WriteLine("\nCasting to an Object and calling Equals:"); Console.WriteLine("person1a and person1b: {0}", ((object) person1a).Equals((object) person1b)); Console.WriteLine("person1a and person2: {0}", ((object) person1a).Equals((object) person2)); } } // The example displays the following output: // person1a and person1b: True // person1a and person2: False // // Casting to an Object and calling Equals: // person1a and person1b: True // person1a and person2: False
// Define a reference type that does not override Equals. type Person(name) = override _.ToString() = name let person1a = Person "John" let person1b = person1a let person2 = Person(string person1a) printfn "Calling Equals:" printfn $"person1a and person1b: {person1a.Equals person1b}" printfn $"person1a and person2: {person1a.Equals person2}" printfn "\nCasting to an Object and calling Equals:" printfn $"person1a and person1b: {(person1a :> obj).Equals(person1b :> obj)}" printfn $"person1a and person2: {(person1a :> obj).Equals(person2 :> obj)}" // The example displays the following output: // person1a and person1b: True // person1a and person2: False // // Casting to an Object and calling Equals: // person1a and person1b: True // person1a and person2: False
' Define a reference type that does not override Equals. Public Class Person1 Private personName As String Public Sub New(name As String) Me.personName = name End Sub Public Overrides Function ToString() As String Return Me.personName End Function End Class Module Example0 Public Sub Main() Dim person1a As New Person1("John") Dim person1b As Person1 = person1a Dim person2 As New Person1(person1a.ToString()) Console.WriteLine("Calling Equals:") Console.WriteLine("person1a and person1b: {0}", person1a.Equals(person1b)) Console.WriteLine("person1a and person2: {0}", person1a.Equals(person2)) Console.WriteLine() Console.WriteLine("Casting to an Object and calling Equals:") Console.WriteLine("person1a and person1b: {0}", CObj(person1a).Equals(CObj(person1b))) Console.WriteLine("person1a and person2: {0}", CObj(person1a).Equals(CObj(person2))) End Sub End Module ' The example displays the following output: ' Calling Equals: ' person1a and person1b: True ' person1a and person2: False ' ' Casting to an Object and calling Equals: ' person1a and person1b: True ' person1a and person2: False
如果目前的實例是實值型別,則 Equals(Object) 方法會測試值是否相等。 值相等表示下列各項:
這兩個物件的類型相同。 如下列範例所示, Byte 值為12的物件不等於值為12的物件,因為兩個 Int32 物件有不同的運行時間類型。
byte value1 = 12; int value2 = 12; object object1 = value1; object object2 = value2; Console.WriteLine("{0} ({1}) = {2} ({3}): {4}", object1, object1.GetType().Name, object2, object2.GetType().Name, object1.Equals(object2)); // The example displays the following output: // 12 (Byte) = 12 (Int32): False
let value1 = 12uy let value2 = 12 let object1 = value1 :> obj let object2 = value2 :> obj printfn $"{object1} ({object1.GetType().Name}) = {object2} ({object2.GetType().Name}): {object1.Equals object2}" // The example displays the following output: // 12 (Byte) = 12 (Int32): False
Module Example2 Public Sub Main() Dim value1 As Byte = 12 Dim value2 As Integer = 12 Dim object1 As Object = value1 Dim object2 As Object = value2 Console.WriteLine("{0} ({1}) = {2} ({3}): {4}", object1, object1.GetType().Name, object2, object2.GetType().Name, object1.Equals(object2)) End Sub End Module ' The example displays the following output: ' 12 (Byte) = 12 (Int32): False
兩個物件之公用和私用字段的值相等。 下列範例會測試值是否相等。 它會定義
Person
結構,這是實值型別,並呼叫Person
類別建構函式來具現化兩個新Person
物件,person1
以及person2
具有相同值的 。 如範例的輸出所示,雖然這兩個物件變數參考不同的物件,person1
而且person2
會相等,因為它們對私personName
用字段具有相同的值。using System; // Define a value type that does not override Equals. public struct Person3 { private string personName; public Person3(string name) { this.personName = name; } public override string ToString() { return this.personName; } } public struct Example3 { public static void Main() { Person3 person1 = new Person3("John"); Person3 person2 = new Person3("John"); Console.WriteLine("Calling Equals:"); Console.WriteLine(person1.Equals(person2)); Console.WriteLine("\nCasting to an Object and calling Equals:"); Console.WriteLine(((object) person1).Equals((object) person2)); } } // The example displays the following output: // Calling Equals: // True // // Casting to an Object and calling Equals: // True
// Define a value type that does not override Equals. [<Struct>] type Person(personName: string) = override _.ToString() = personName let person1 = Person "John" let person2 = Person "John" printfn "Calling Equals:" printfn $"{person1.Equals person2}" printfn $"\nCasting to an Object and calling Equals:" printfn $"{(person1 :> obj).Equals(person2 :> obj)}" // The example displays the following output: // Calling Equals: // True // // Casting to an Object and calling Equals: // True
' Define a value type that does not override Equals. Public Structure Person4 Private personName As String Public Sub New(name As String) Me.personName = name End Sub Public Overrides Function ToString() As String Return Me.personName End Function End Structure Module Example4 Public Sub Main() Dim p1 As New Person4("John") Dim p2 As New Person4("John") Console.WriteLine("Calling Equals:") Console.WriteLine(p1.Equals(p2)) Console.WriteLine() Console.WriteLine("Casting to an Object and calling Equals:") Console.WriteLine(CObj(p1).Equals(p2)) End Sub End Module ' The example displays the following output: ' Calling Equals: ' True ' ' Casting to an Object and calling Equals: ' True
因為類別 Object 是 .NET 中所有型別的基類,因此 Object.Equals(Object) 方法會提供所有其他類型的默認相等比較。 不過,類型通常會覆寫 Equals 方法來實作值相等。 如需詳細資訊,請參閱呼叫端的附註和繼承者注意事項小節。
Windows 執行階段 注意事項
當您在 Windows 執行階段 的類別上呼叫 Equals(Object) 方法多載時,它會為未覆寫 Equals(Object)的類別提供默認行為。 這是 .NET 為 Windows 執行階段 提供的支援的一部分(請參閱 Windows 市集應用程式和 Windows 執行階段 的 .NET 支援)。 Windows 執行階段 中的類別不會繼承 Object,而且目前不會實Equals(Object)作 方法。 不過,當您在 C# 或 Visual Basic 程式代碼中使用、 和方法時,它們似乎有 ToStringEquals(Object)、 和 GetHashCode 方法,而 .NET 會提供這些方法的預設行為。
注意
Windows 執行階段 以 C# 或 Visual Basic 撰寫的類別可以覆寫Equals(Object)方法多載。
來電者注意事項
衍生類別經常覆寫 方法, Object.Equals(Object) 以實作值相等。 此外,類型也會經常透過實IEquatable<T>作 介面,將額外的強型別多載Equals
提供給方法。 當您呼叫 Equals
方法來測試是否相等時,您應該知道目前的實例是否覆寫 Object.Equals 並瞭解如何解析方法的特定呼叫 Equals
。 否則,您可能會執行與預期不同之相等的測試,而且方法可能會傳回非預期的值。
下列範例提供一個實例。 它會具現化三 StringBuilder 個具有相同字串的對象,然後對方法進行四次呼叫 Equals
。 第一個方法呼叫會傳 true
回 ,其餘三個傳回 false
。
using System;
using System.Text;
public class Example5
{
public static void Main()
{
StringBuilder sb1 = new StringBuilder("building a string...");
StringBuilder sb2 = new StringBuilder("building a string...");
Console.WriteLine("sb1.Equals(sb2): {0}", sb1.Equals(sb2));
Console.WriteLine("((Object) sb1).Equals(sb2): {0}",
((Object) sb1).Equals(sb2));
Console.WriteLine("Object.Equals(sb1, sb2): {0}",
Object.Equals(sb1, sb2));
Object sb3 = new StringBuilder("building a string...");
Console.WriteLine("\nsb3.Equals(sb2): {0}", sb3.Equals(sb2));
}
}
// The example displays the following output:
// sb1.Equals(sb2): True
// ((Object) sb1).Equals(sb2): False
// Object.Equals(sb1, sb2): False
//
// sb3.Equals(sb2): False
open System
open System.Text
let sb1 = StringBuilder "building a string..."
let sb2 = StringBuilder "building a string..."
printfn $"sb1.Equals(sb2): {sb1.Equals sb2}"
printfn $"((Object) sb1).Equals(sb2): {(sb1 :> obj).Equals sb2}"
printfn $"Object.Equals(sb1, sb2): {Object.Equals(sb1, sb2)}"
let sb3 = StringBuilder "building a string..."
printfn $"\nsb3.Equals(sb2): {sb3.Equals sb2}"
// The example displays the following output:
// sb1.Equals(sb2): True
// ((Object) sb1).Equals(sb2): False
// Object.Equals(sb1, sb2): False
//
// sb3.Equals(sb2): False
Imports System.Text
Module Example5
Public Sub Main()
Dim sb1 As New StringBuilder("building a string...")
Dim sb2 As New StringBuilder("building a string...")
Console.WriteLine("sb1.Equals(sb2): {0}", sb1.Equals(sb2))
Console.WriteLine("CObj(sb1).Equals(sb2): {0}",
CObj(sb1).Equals(sb2))
Console.WriteLine("Object.Equals(sb1, sb2): {0}",
Object.Equals(sb1, sb2))
Console.WriteLine()
Dim sb3 As Object = New StringBuilder("building a string...")
Console.WriteLine("sb3.Equals(sb2): {0}", sb3.Equals(sb2))
End Sub
End Module
' The example displays the following output:
' sb1.Equals(sb2): True
' CObj(sb1).Equals(sb2): False
' Object.Equals(sb1, sb2): False
'
' sb3.Equals(sb2): False
在第一個案例中,會呼叫測試值相等的強型 StringBuilder.Equals(StringBuilder) 別方法多載。 由於指派給兩 StringBuilder 個物件的字串相等,因此 方法會傳 true
回 。 不過, StringBuilder 不會覆寫 Object.Equals(Object)。 因此,當物件轉換成 Object時,當StringBuilder實例指派給 類型的Object變數,而當方法傳遞兩StringBuilder個StringBuilder物件時Object.Equals(Object, Object),就會呼叫預設Object.Equals(Object)方法。 因為 StringBuilder 是參考型別,這相當於將兩 StringBuilder 個對象傳遞至 ReferenceEquals 方法。 雖然這三 StringBuilder 個物件都包含相同的字串,但是它們會參考三個不同的物件。 因此,這三個方法呼叫會傳回 false
。
您可以呼叫 ReferenceEquals 方法,將目前的 物件與另一個對象進行比較,以取得參考相等性。 在 Visual Basic 中,您也可以使用 is
關鍵詞 (例如 , If Me Is otherObject Then ...
)。
繼承者的注意事項
當您定義自己的類型時,該類型會繼承其基底類型方法所 Equals
定義的功能。 下表列出 .NET 中類型主要類別之方法的預設實 Equals
作。
型別分類 | 所定義的相等 | 註解 |
---|---|---|
直接衍生自的類別 Object | Object.Equals(Object) | 參考相等;相當於通話 Object.ReferenceEquals。 |
結構 | ValueType.Equals | 值相等;使用反映直接位元組比較或欄位段逐欄位比較。 |
列舉型別 | Enum.Equals | 值必須具有相同的列舉型別和相同的基礎值。 |
Delegate | MulticastDelegate.Equals | 委派的型別必須具有相同的調用清單。 |
介面 | Object.Equals(Object) | 參考相等。 |
針對實值型別,您應該一律覆寫 Equals,因為測試依賴反映的相等會提供不佳的效能。 您也可以覆寫參考型別的默認實 Equals 作,以測試值是否相等,而不是參考相等,並定義值相等的精確意義。 如果兩個物件具有相同值,則傳回true
的Equals這類實作即使不是相同的實例也一樣。 類型的實作器會決定構成物件值的內容,但通常是對象實例變數中儲存的部分或所有數據。 例如,物件的值是以字串的 String 字元為基礎; String.Equals(Object) 方法會覆寫 Object.Equals(Object) 方法,以傳回 true
以相同順序包含相同字元的任何兩個字元串實例。
下列範例示範如何覆寫 Object.Equals(Object) 方法來測試值是否相等。 它會覆寫 Equals 類別的 Person
方法。 如果 Person
接受其基類實作相等,則只有參考單一物件時,兩 Person
個物件才會相等。 不過,在此情況下,如果兩個 Person
物件具有屬性的相同值 Person.Id
,則兩個物件相等。
public class Person6
{
private string idNumber;
private string personName;
public Person6(string name, string id)
{
this.personName = name;
this.idNumber = id;
}
public override bool Equals(Object obj)
{
Person6 personObj = obj as Person6;
if (personObj == null)
return false;
else
return idNumber.Equals(personObj.idNumber);
}
public override int GetHashCode()
{
return this.idNumber.GetHashCode();
}
}
public class Example6
{
public static void Main()
{
Person6 p1 = new Person6("John", "63412895");
Person6 p2 = new Person6("Jack", "63412895");
Console.WriteLine(p1.Equals(p2));
Console.WriteLine(Object.Equals(p1, p2));
}
}
// The example displays the following output:
// True
// True
open System
type Person(name, id) =
member _.Name = name
member _.Id = id
override _.Equals(obj) =
match obj with
| :? Person as personObj ->
id.Equals personObj.Id
| _ ->
false
override _.GetHashCode() =
id.GetHashCode()
let p1 = Person("John", "63412895")
let p2 = Person("Jack", "63412895")
printfn $"{p1.Equals p2}"
printfn $"{Object.Equals(p1, p2)}"
// The example displays the following output:
// True
// True
Public Class Person
Private idNumber As String
Private personName As String
Public Sub New(name As String, id As String)
Me.personName = name
Me.idNumber = id
End Sub
Public Overrides Function Equals(obj As Object) As Boolean
Dim personObj As Person = TryCast(obj, Person)
If personObj Is Nothing Then
Return False
Else
Return idNumber.Equals(personObj.idNumber)
End If
End Function
Public Overrides Function GetHashCode() As Integer
Return Me.idNumber.GetHashCode()
End Function
End Class
Module Example6
Public Sub Main()
Dim p1 As New Person("John", "63412895")
Dim p2 As New Person("Jack", "63412895")
Console.WriteLine(p1.Equals(p2))
Console.WriteLine(Object.Equals(p1, p2))
End Sub
End Module
' The example displays the following output:
' True
' True
除了覆寫 Equals之外,您還可以實 IEquatable<T> 作 介面,以提供強型別測試是否相等。
方法的所有實作 Equals(Object) 都必須有下列語句。 在清單中, x
、 y
和 z
代表非 Null 的物件參考。
x.Equals(x)
傳回true
。x.Equals(y)
會傳回與y.Equals(x)
相同的值。x.Equals(y)
如果 與y
都是x
NaN
,則傳true
回 。如果
(x.Equals(y) && y.Equals(z))
傳true
回 ,則會x.Equals(z)
傳true
回 。只要和
x
y
所參考的物件未修改,後續呼叫會x.Equals(y)
傳回相同的值。x.Equals(null)
傳回false
。
的 Equals 實作不得擲回例外狀況;它們應該一律傳回值。 例如,如果 obj
是 ,則Equals方法應該傳回 false
,而不是擲回 ArgumentNullExceptionnull
。
覆寫 Equals(Object)時,請遵循下列指導方針:
實作 IComparable 的類型必須覆寫 Equals(Object)。
覆寫 Equals(Object) 的類型也必須覆寫 GetHashCode,否則哈希表可能無法正常運作。
您應該考慮實作 IEquatable<T> 介面,以支持強型別測試是否相等。 您的 IEquatable<T>.Equals 實作應該會傳回與 Equals一致的結果。
如果您的程式設計語言支援運算符多載,而且您多載指定類型的相等運算符,您也必須覆寫 Equals(Object) 方法,以傳回與相等運算符相同的結果。 這有助於確保使用 Equals (例如 ArrayList 和 Hashtable) 的類別庫程式代碼的行為方式與應用程式程式代碼使用相等運算符的方式一致。
參考型別的指導方針
下列指導方針適用於覆寫 Equals(Object) 參考型別:
如果型別的語意是以類型代表某些值的事實為基礎,請考慮覆 Equals 寫 。
大部分的參考型別都不能多載等號運算符,即使它們覆寫 Equals也一樣。 不過,如果您實作的參考型別是要有值語意,例如複數類型,則必須覆寫等號運算符。
您不應該覆寫 Equals 可變動的參考類型。 這是因為覆寫 Equals 需要您也覆寫 GetHashCode 方法,如上一節所述。 這表示可變參考型別實例的哈希碼在其存留期內可能會變更,這可能會導致物件在哈希表中遺失。
實值型別的指導方針
下列指導方針適用於覆寫 Equals(Object) 實值型別:
如果您要定義包含一或多個字段的實值型別,其值是參考型別,您應該覆寫 Equals(Object)。 Equals(Object)提供的ValueType實作會針對欄位為所有實值型別的值型別執行位元組位元組比較,但它會使用反映來執行包含參考型別之實值型別的逐位元段比較。
如果您覆寫 Equals ,開發語言支援運算元多載,則必須多載等號運算元。
您應該實作 IEquatable<T> 介面。 呼叫強型別IEquatable<T>.Equals方法可避免將自變數 Boxing。
obj
範例
下列範例顯示 Point
覆寫 Equals 方法以提供值相等的類別,以及 Point3D
衍生自 Point
的類別。 因為 Point
覆寫 Object.Equals(Object) 以測試值是否相等, Object.Equals(Object) 因此不會呼叫 方法。 不過, Point3D.Equals
呼叫 Point.Equals
,因為 Point
Object.Equals(Object) 會以提供值相等的方式實作。
using System;
class Point2
{
protected int x, y;
public Point2() : this(0, 0)
{ }
public Point2(int x, int y)
{
this.x = x;
this.y = y;
}
public override bool Equals(Object obj)
{
//Check for null and compare run-time types.
if ((obj == null) || !this.GetType().Equals(obj.GetType()))
{
return false;
}
else
{
Point2 p = (Point2)obj;
return (x == p.x) && (y == p.y);
}
}
public override int GetHashCode()
{
return (x << 2) ^ y;
}
public override string ToString()
{
return String.Format("Point2({0}, {1})", x, y);
}
}
sealed class Point3D : Point2
{
int z;
public Point3D(int x, int y, int z) : base(x, y)
{
this.z = z;
}
public override bool Equals(Object obj)
{
Point3D pt3 = obj as Point3D;
if (pt3 == null)
return false;
else
return base.Equals((Point2)obj) && z == pt3.z;
}
public override int GetHashCode()
{
return (base.GetHashCode() << 2) ^ z;
}
public override String ToString()
{
return String.Format("Point2({0}, {1}, {2})", x, y, z);
}
}
class Example7
{
public static void Main()
{
Point2 point2D = new Point2(5, 5);
Point3D point3Da = new Point3D(5, 5, 2);
Point3D point3Db = new Point3D(5, 5, 2);
Point3D point3Dc = new Point3D(5, 5, -1);
Console.WriteLine("{0} = {1}: {2}",
point2D, point3Da, point2D.Equals(point3Da));
Console.WriteLine("{0} = {1}: {2}",
point2D, point3Db, point2D.Equals(point3Db));
Console.WriteLine("{0} = {1}: {2}",
point3Da, point3Db, point3Da.Equals(point3Db));
Console.WriteLine("{0} = {1}: {2}",
point3Da, point3Dc, point3Da.Equals(point3Dc));
}
}
// The example displays the following output:
// Point2(5, 5) = Point2(5, 5, 2): False
// Point2(5, 5) = Point2(5, 5, 2): False
// Point2(5, 5, 2) = Point2(5, 5, 2): True
// Point2(5, 5, 2) = Point2(5, 5, -1): False
type Point(x, y) =
new () = Point(0, 0)
member _.X = x
member _.Y = y
override _.Equals(obj) =
//Check for null and compare run-time types.
match obj with
| :? Point as p ->
x = p.X && y = p.Y
| _ ->
false
override _.GetHashCode() =
(x <<< 2) ^^^ y
override _.ToString() =
$"Point({x}, {y})"
type Point3D(x, y, z) =
inherit Point(x, y)
member _.Z = z
override _.Equals(obj) =
match obj with
| :? Point3D as pt3 ->
base.Equals(pt3 :> Point) && z = pt3.Z
| _ ->
false
override _.GetHashCode() =
(base.GetHashCode() <<< 2) ^^^ z
override _.ToString() =
$"Point({x}, {y}, {z})"
let point2D = Point(5, 5)
let point3Da = Point3D(5, 5, 2)
let point3Db = Point3D(5, 5, 2)
let point3Dc = Point3D(5, 5, -1)
printfn $"{point2D} = {point3Da}: {point2D.Equals point3Da}"
printfn $"{point2D} = {point3Db}: {point2D.Equals point3Db}"
printfn $"{point3Da} = {point3Db}: {point3Da.Equals point3Db}"
printfn $"{point3Da} = {point3Dc}: {point3Da.Equals point3Dc}"
// The example displays the following output:
// Point(5, 5) = Point(5, 5, 2): False
// Point(5, 5) = Point(5, 5, 2): False
// Point(5, 5, 2) = Point(5, 5, 2): True
// Point(5, 5, 2) = Point(5, 5, -1): False
Class Point1
Protected x, y As Integer
Public Sub New()
Me.x = 0
Me.y = 0
End Sub
Public Sub New(x As Integer, y As Integer)
Me.x = x
Me.y = y
End Sub
Public Overrides Function Equals(obj As Object) As Boolean
' Check for null and compare run-time types.
If obj Is Nothing OrElse Not Me.GetType().Equals(obj.GetType()) Then
Return False
Else
Dim p As Point1 = DirectCast(obj, Point1)
Return x = p.x AndAlso y = p.y
End If
End Function
Public Overrides Function GetHashCode() As Integer
Return (x << 2) Xor y
End Function
Public Overrides Function ToString() As String
Return String.Format("Point1({0}, {1})", x, y)
End Function
End Class
Class Point3D : Inherits Point1
Private z As Integer
Public Sub New(ByVal x As Integer, ByVal y As Integer, ByVal z As Integer)
MyBase.New(x, y)
Me.z = z
End Sub
Public Overrides Function Equals(ByVal obj As Object) As Boolean
Dim pt3 As Point3D = TryCast(obj, Point3D)
If pt3 Is Nothing Then
Return False
Else
Return MyBase.Equals(CType(pt3, Point1)) AndAlso z = pt3.z
End If
End Function
Public Overrides Function GetHashCode() As Integer
Return (MyBase.GetHashCode() << 2) Xor z
End Function
Public Overrides Function ToString() As String
Return String.Format("Point1({0}, {1}, {2})", x, y, z)
End Function
End Class
Module Example1
Public Sub Main()
Dim point2D As New Point1(5, 5)
Dim point3Da As New Point3D(5, 5, 2)
Dim point3Db As New Point3D(5, 5, 2)
Dim point3Dc As New Point3D(5, 5, -1)
Console.WriteLine("{0} = {1}: {2}",
point2D, point3Da, point2D.Equals(point3Da))
Console.WriteLine("{0} = {1}: {2}",
point2D, point3Db, point2D.Equals(point3Db))
Console.WriteLine("{0} = {1}: {2}",
point3Da, point3Db, point3Da.Equals(point3Db))
Console.WriteLine("{0} = {1}: {2}",
point3Da, point3Dc, point3Da.Equals(point3Dc))
End Sub
End Module
' The example displays the following output
' Point1(5, 5) = Point1(5, 5, 2): False
' Point1(5, 5) = Point1(5, 5, 2): False
' Point1(5, 5, 2) = Point1(5, 5, 2): True
' Point1(5, 5, 2) = Point1(5, 5, -1): False
方法 Point.Equals
會檢查以確定 obj
自變數不是 Null ,而且它參考與這個物件相同類型的實例。 如果任一項檢查失敗,方法會傳 false
回 。
方法 Point.Equals
會呼叫 GetType 方法,以判斷兩個 對象的運行時間類型是否相同。 如果 方法在 C# 或 TryCast(obj, Point)
Visual Basic 中使用表單obj is Point
的檢查,則檢查會傳回 true
,如果 是 obj
衍生類別Point
的實例,即使 obj
和 目前的實例不是相同的運行時間類型。 確認這兩個物件的類型相同,方法會轉換成 obj
類型 Point
,並傳回比較兩個對象的實例欄位的結果。
在 中Point3D.Equals
,會覆寫 Object.Equals(Object)的繼承Point.Equals
方法會在完成任何其他動作之前叫用 。 因為 Point3D
是密封類別 (NotInheritable
在 Visual Basic 中),因此在 C# 或 TryCast(obj, Point)
Visual Basic 中籤入表單obj is Point
就足以確保obj
為 Point3D
物件。 Point3D
如果是 物件,則會轉換成 Point
物件,並傳遞至的基類實作Equals。 只有當繼承 Point.Equals
的方法傳回 true
時,方法才會比較 z
衍生類別中引進的實例欄位。
下列範例會定義類別,該類別會在內部將矩形實作為兩Point
個 Rectangle
物件。 類別 Rectangle
也會覆寫 Object.Equals(Object) 以提供值相等。
using System;
class Rectangle
{
private Point a, b;
public Rectangle(int upLeftX, int upLeftY, int downRightX, int downRightY)
{
this.a = new Point(upLeftX, upLeftY);
this.b = new Point(downRightX, downRightY);
}
public override bool Equals(Object obj)
{
// Perform an equality check on two rectangles (Point object pairs).
if (obj == null || GetType() != obj.GetType())
return false;
Rectangle r = (Rectangle)obj;
return a.Equals(r.a) && b.Equals(r.b);
}
public override int GetHashCode()
{
return Tuple.Create(a, b).GetHashCode();
}
public override String ToString()
{
return String.Format("Rectangle({0}, {1}, {2}, {3})",
a.x, a.y, b.x, b.y);
}
}
class Point
{
internal int x;
internal int y;
public Point(int X, int Y)
{
this.x = X;
this.y = Y;
}
public override bool Equals (Object obj)
{
// Performs an equality check on two points (integer pairs).
if (obj == null || GetType() != obj.GetType()) return false;
Point p = (Point)obj;
return (x == p.x) && (y == p.y);
}
public override int GetHashCode()
{
return Tuple.Create(x, y).GetHashCode();
}
}
class Example
{
public static void Main()
{
Rectangle r1 = new Rectangle(0, 0, 100, 200);
Rectangle r2 = new Rectangle(0, 0, 100, 200);
Rectangle r3 = new Rectangle(0, 0, 150, 200);
Console.WriteLine("{0} = {1}: {2}", r1, r2, r1.Equals(r2));
Console.WriteLine("{0} = {1}: {2}", r1, r3, r1.Equals(r3));
Console.WriteLine("{0} = {1}: {2}", r2, r3, r2.Equals(r3));
}
}
// The example displays the following output:
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
type Point(x, y) =
member _.X = x
member _.Y = y
override _.Equals(obj) =
// Performs an equality check on two points (integer pairs).
match obj with
| :? Point as p ->
x = p.X && y = p.Y
| _ ->
false
override _.GetHashCode() =
(x, y).GetHashCode()
type Rectangle(upLeftX, upLeftY, downRightX, downRightY) =
let a = Point(upLeftX, upLeftY)
let b = Point(downRightX, downRightY)
member _.UpLeft = a
member _.DownRight = b
override _.Equals(obj) =
// Perform an equality check on two rectangles (Point object pairs).
match obj with
| :? Rectangle as r ->
a.Equals(r.UpLeft) && b.Equals(r.DownRight)
| _ ->
false
override _.GetHashCode() =
(a, b).GetHashCode()
override _.ToString() =
$"Rectangle({a.X}, {a.Y}, {b.X}, {b.Y})"
let r1 = Rectangle(0, 0, 100, 200)
let r2 = Rectangle(0, 0, 100, 200)
let r3 = Rectangle(0, 0, 150, 200)
printfn $"{r1} = {r2}: {r1.Equals r2}"
printfn $"{r1} = {r3}: {r1.Equals r3}"
printfn $"{r2} = {r3}: {r2.Equals r3}"
// The example displays the following output:
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
// Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
Class Rectangle
Private a, b As Point
Public Sub New(ByVal upLeftX As Integer, ByVal upLeftY As Integer, _
ByVal downRightX As Integer, ByVal downRightY As Integer)
Me.a = New Point(upLeftX, upLeftY)
Me.b = New Point(downRightX, downRightY)
End Sub
Public Overrides Function Equals(ByVal obj As [Object]) As Boolean
' Performs an equality check on two rectangles (Point object pairs).
If obj Is Nothing OrElse Not [GetType]().Equals(obj.GetType()) Then
Return False
End If
Dim r As Rectangle = CType(obj, Rectangle)
Return a.Equals(r.a) AndAlso b.Equals(r.b)
End Function
Public Overrides Function GetHashCode() As Integer
Return Tuple.Create(a, b).GetHashCode()
End Function
Public Overrides Function ToString() As String
Return String.Format("Rectangle({0}, {1}, {2}, {3})",
a.x, a.y, b.x, b.y)
End Function
End Class
Class Point
Friend x As Integer
Friend y As Integer
Public Sub New(ByVal X As Integer, ByVal Y As Integer)
Me.x = X
Me.y = Y
End Sub
Public Overrides Function Equals(ByVal obj As [Object]) As Boolean
' Performs an equality check on two points (integer pairs).
If obj Is Nothing OrElse Not [GetType]().Equals(obj.GetType()) Then
Return False
Else
Dim p As Point = CType(obj, Point)
Return x = p.x AndAlso y = p.y
End If
End Function
Public Overrides Function GetHashCode() As Integer
Return Tuple.Create(x, y).GetHashCode()
End Function
End Class
Class Example
Public Shared Sub Main()
Dim r1 As New Rectangle(0, 0, 100, 200)
Dim r2 As New Rectangle(0, 0, 100, 200)
Dim r3 As New Rectangle(0, 0, 150, 200)
Console.WriteLine("{0} = {1}: {2}", r1, r2, r1.Equals(r2))
Console.WriteLine("{0} = {1}: {2}", r1, r3, r1.Equals(r3))
Console.WriteLine("{0} = {1}: {2}", r2, r3, r2.Equals(r3))
End Sub
End Class
' The example displays the following output:
' Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 100, 200): True
' Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
' Rectangle(0, 0, 100, 200) = Rectangle(0, 0, 150, 200): False
某些語言,例如 C# 和 Visual Basic 支援運算子多載。 當類型多載等號運算符時,它也必須覆寫 Equals(Object) 方法以提供相同的功能。 這通常是藉由以多載相等運算符來撰寫 Equals(Object) 方法來完成,如下列範例所示。
using System;
public struct Complex
{
public double re, im;
public override bool Equals(Object obj)
{
return obj is Complex && this == (Complex)obj;
}
public override int GetHashCode()
{
return Tuple.Create(re, im).GetHashCode();
}
public static bool operator ==(Complex x, Complex y)
{
return x.re == y.re && x.im == y.im;
}
public static bool operator !=(Complex x, Complex y)
{
return !(x == y);
}
public override String ToString()
{
return String.Format("({0}, {1})", re, im);
}
}
class MyClass
{
public static void Main()
{
Complex cmplx1, cmplx2;
cmplx1.re = 4.0;
cmplx1.im = 1.0;
cmplx2.re = 2.0;
cmplx2.im = 1.0;
Console.WriteLine("{0} <> {1}: {2}", cmplx1, cmplx2, cmplx1 != cmplx2);
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2));
cmplx2.re = 4.0;
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1 == cmplx2);
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2));
}
}
// The example displays the following output:
// (4, 1) <> (2, 1): True
// (4, 1) = (2, 1): False
// (4, 1) = (4, 1): True
// (4, 1) = (4, 1): True
[<Struct; CustomEquality; NoComparison>]
type Complex =
val mutable re: double
val mutable im: double
override this.Equals(obj) =
match obj with
| :? Complex as c when c = this -> true
| _ -> false
override this.GetHashCode() =
(this.re, this.im).GetHashCode()
override this.ToString() =
$"({this.re}, {this.im})"
static member op_Equality (x: Complex, y: Complex) =
x.re = y.re && x.im = y.im
static member op_Inequality (x: Complex, y: Complex) =
x = y |> not
let mutable cmplx1 = Complex()
let mutable cmplx2 = Complex()
cmplx1.re <- 4.0
cmplx1.im <- 1.0
cmplx2.re <- 2.0
cmplx2.im <- 1.0
printfn $"{cmplx1} <> {cmplx2}: {cmplx1 <> cmplx2}"
printfn $"{cmplx1} = {cmplx2}: {cmplx1.Equals cmplx2}"
cmplx2.re <- 4.0
printfn $"{cmplx1} = {cmplx2}: {cmplx1 = cmplx2}"
printfn $"{cmplx1} = {cmplx2}: {cmplx1.Equals cmplx2}"
// The example displays the following output:
// (4, 1) <> (2, 1): True
// (4, 1) = (2, 1): False
// (4, 1) = (4, 1): True
// (4, 1) = (4, 1): True
Public Structure Complex
Public re, im As Double
Public Overrides Function Equals(ByVal obj As [Object]) As Boolean
Return TypeOf obj Is Complex AndAlso Me = CType(obj, Complex)
End Function
Public Overrides Function GetHashCode() As Integer
Return Tuple.Create(re, im).GetHashCode()
End Function
Public Shared Operator = (x As Complex, y As Complex) As Boolean
Return x.re = y.re AndAlso x.im = y.im
End Operator
Public Shared Operator <> (x As Complex, y As Complex) As Boolean
Return Not (x = y)
End Operator
Public Overrides Function ToString() As String
Return String.Format("({0}, {1})", re, im)
End Function
End Structure
Class Example8
Public Shared Sub Main()
Dim cmplx1, cmplx2 As Complex
cmplx1.re = 4.0
cmplx1.im = 1.0
cmplx2.re = 2.0
cmplx2.im = 1.0
Console.WriteLine("{0} <> {1}: {2}", cmplx1, cmplx2, cmplx1 <> cmplx2)
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2))
cmplx2.re = 4.0
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1 = cmplx2)
Console.WriteLine("{0} = {1}: {2}", cmplx1, cmplx2, cmplx1.Equals(cmplx2))
End Sub
End Class
' The example displays the following output:
' (4, 1) <> (2, 1): True
' (4, 1) = (2, 1): False
' (4, 1) = (4, 1): True
' (4, 1) = (4, 1): True
因為 Complex
是實值型別,所以無法衍生自 。 因此,對方法的覆寫 Equals(Object) 不需要呼叫 GetType 來判斷每個對象的精確運行時間類型,但可以改用 is
C# 中的 運算符或 TypeOf
Visual Basic 中的 運算符來檢查參數的類型 obj
。