complex<long double>

發行項
06/09/2015

描述儲存已排序的物件對兩個 long double型別，第一個代表複數的實數部分和第二個代表虛數物件。

template<>
   class complex<long double> {
public:
   complex(
      long double _RealVal = 0, 
      long double _ImagVal = 0
   );
complex(
      const complex<long double>& _ComplexNum
   );
   // rest same as template class complex
};

參數

_RealVal
型別 long double 的值複數的實數部分的建構。
_ImagVal
型別 long double 的值複數的虛數部分的建構。
_ComplexNum
型別 double 複數實數及虛數用來初始化型別建構的 long double 複數的或型別 float 。

傳回值

long double型別的數目。

備註

樣板類別複雜的明確特製化的 long double 型別的複雜類別的與它所定義的範本只有類別有建構函式。從 long double 轉換為 float 允許是隱含的，不過，到 long double 要求從 double 的轉換是 explicit。使用指派語法，使用 explicit 排除與型別轉換的初始。

如需範本類別 complex，請參閱 complex 類別。如需範本類別 complex成員的清單，請參閱複雜的成員。

範例

// complex_comp_ld.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // The first constructor specifies real & imaginary parts
   complex <long double> c1 ( 4.0 , 5.0 );
   cout << "Specifying initial real & imaginary parts,\n"
        << " as type float gives c1 = " << c1 << endl;

   // The second constructor initializes values of the real &
   // imaginary parts using those of complex number of type float
   complex <float> c2float ( 1.0 , 3.0 );
   complex <long double> c2longdouble ( c2float );
   cout << "Implicit conversion from type float to type long double,"
        << "\n gives c2longdouble = " << c2longdouble << endl;

   // The third constructor initializes values of the real &
   // imaginary parts using those of a complex number
   // of type double
   complex <double> c3double ( 3.0 , 4.0 );
   complex <long double> c3longdouble ( c3double );
   cout << "Implicit conversion from type long double to type float,"
        << "\n gives c3longdouble = " << c3longdouble << endl;

   // The modulus and argument of a complex number can be recovered
   double absc3 = abs ( c3longdouble );
   double argc3 = arg ( c3longdouble );
   cout << "The modulus of c3 is recovered from c3 using: abs ( c3 ) = "
        << absc3 << endl;
   cout << "Argument of c3 is recovered from c3 using:\n arg ( c3 ) = "
        << argc3 << " radians, which is " << argc3 * 180 / pi
        << " degrees." << endl;
}