HOW TO：改善 TreeView 的效能
如果 TreeView 包含許多項目，則所需要的載入時間量可能會造成使用者介面明顯延後。 藉由將 VirtualizingStackPanel.IsVirtualizing 附加屬性設為 true，即可以改善載入時間。 當使用者透過使用滑鼠滾輪或是拖曳捲軸的捲動方塊，捲動 TreeView 時，UI 的反應可能也會很慢。 藉由將 VirtualizingStackPanel.VirtualizationMode 附加屬性設為 Recycling，即可以改善使用者捲動時的 TreeView 效能。
範例
說明
下列範例建立的 TreeView 會將 VirtualizingStackPanel.IsVirtualizing 設為 true，並將 VirtualizingStackPanel.VirtualizationMode 設為 Recycling，以最佳化其效能。
程式碼
<StackPanel>
<StackPanel.Resources>
<src:TreeViewData x:Key="dataItems"/>
<HierarchicalDataTemplate DataType="{x:Type src:ItemsForTreeView}"
ItemsSource="{Binding Path=SecondLevelItems}">
<!--Display the TopLevelName property in the first level.-->
<TextBlock Text="{Binding Path=TopLevelName}"/>
<!--Display each string in the SecondLevelItems property in
the second level.-->
<HierarchicalDataTemplate.ItemTemplate>
<DataTemplate>
<TextBlock Text="{Binding}"/>
</DataTemplate>
</HierarchicalDataTemplate.ItemTemplate>
<!--Set the foreground of the items in the second level
to Navy.-->
<HierarchicalDataTemplate.ItemContainerStyle>
<Style TargetType="TreeViewItem">
<Setter Property="Foreground" Value="Navy"/>
</Style>
</HierarchicalDataTemplate.ItemContainerStyle>
</HierarchicalDataTemplate>
</StackPanel.Resources>
<TreeView Height="200"
ItemsSource="{Binding Source={StaticResource dataItems}}"
VirtualizingStackPanel.IsVirtualizing="True"
VirtualizingStackPanel.VirtualizationMode="Recycling">
<TreeView.ItemContainerStyle>
<!--Expand each TreeViewItem in the first level and
set its foreground to Green.-->
<Style TargetType="TreeViewItem">
<Setter Property="IsExpanded" Value="True"/>
<Setter Property="Foreground" Value="Green"/>
</Style>
</TreeView.ItemContainerStyle>
</TreeView>
</StackPanel>
下列範例顯示前述範例使用的資料。
Public Class TreeViewData
Inherits ObservableCollection(Of ItemsForTreeView)
Public Sub New()
For i As Integer = 0 To 99
Dim item As New ItemsForTreeView()
item.TopLevelName = "item " & i.ToString()
Add(item)
Next
End Sub
End Class
Public Class ItemsForTreeView
Private _TopLevelName As String
Public Property TopLevelName() As String
Get
Return _TopLevelName
End Get
Set(ByVal value As String)
_TopLevelName = value
End Set
End Property
Private level2Items As ObservableCollection(Of String)
Public ReadOnly Property SecondLevelItems() As ObservableCollection(Of String)
Get
If level2Items Is Nothing Then
level2Items = New ObservableCollection(Of String)()
End If
Return level2Items
End Get
End Property
Public Sub New()
For i As Integer = 0 To 9
SecondLevelItems.Add("Second Level " & i.ToString())
Next
End Sub
End Class
public class TreeViewData : ObservableCollection<ItemsForTreeView>
{
public TreeViewData()
{
for (int i = 0; i < 100; ++i)
{
ItemsForTreeView item = new ItemsForTreeView();
item.TopLevelName = "item " + i.ToString();
Add(item);
}
}
}
public class ItemsForTreeView
{
public string TopLevelName { get; set; }
private ObservableCollection<string> level2Items;
public ObservableCollection<string> SecondLevelItems
{
get
{
if (level2Items == null)
{
level2Items = new ObservableCollection<string>();
}
return level2Items;
}
}
public ItemsForTreeView()
{
for (int i = 0; i < 10; ++i)
{
SecondLevelItems.Add("Second Level " + i.ToString());
}
}
}