SqlGeometry.STWithin 方法

Determines whether the current SqlGeometry is completely within the specified SqlGeometry instance.

命名空間：  Microsoft.SqlServer.Types
組件：  Microsoft.SqlServer.Types (在 Microsoft.SqlServer.Types.dll 中)

語法

'宣告
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STWithin ( _
    other As SqlGeometry _
) As SqlBoolean
'用途
Dim instance As SqlGeometry 
Dim other As SqlGeometry 
Dim returnValue As SqlBoolean 

returnValue = instance.STWithin(other)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STWithin(
    SqlGeometry other
)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STWithin(
    SqlGeometry^ other
)

[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STWithin : 
        other:SqlGeometry -> SqlBoolean

public function STWithin(
    other : SqlGeometry
) : SqlBoolean

參數

• other
  型別：Microsoft.SqlServer.Types.SqlGeometry
  The SqlGeometry instance to compare to the current SqlGeometry.

傳回值

型別：System.Data.SqlTypes.SqlBoolean
Returns true if a SqlGeometry instance is completely within another SqlGeometry instance; otherwise, returns false.

備註

This method always returns nullnull 參考 (在 Visual Basic 中為 Nothing) if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.

請參閱

參考

SqlGeometry 類別

Microsoft.SqlServer.Types 命名空間