Job.Start 方法
Runs the referenced job.
命名空間： Microsoft.SqlServer.Management.Smo.Agent
組件： Microsoft.SqlServer.Smo (在 Microsoft.SqlServer.Smo.dll 中)
語法
'宣告
Public Sub Start
'用途
Dim instance As Job
instance.Start()
public void Start()
public:
void Start()
member Start : unit -> unit
public function Start()
範例
The following code example creates a job and starts it.
C#
Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
JobStep jbstp = new JobStep(jb, "Test Job Step");
jbstp.OnSuccessAction = StepCompletionAction.QuitWithSuccess;
jbstp.OnFailAction = StepCompletionAction.QuitWithFailure;
jbstp.Create();
jb.ApplyToTargetServer(srv.Name);
jb.IsEnabled = true;
jb.Start();
PowerShell
$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Testrrt Job")
$jb.Create()
$jbstp = new-object Microsoft.SqlServer.Management.Smo.Agent.JobStep($jb, "Test Job Step")
$jbstp.OnSuccessAction = [Microsoft.SqlServer.Management.Smo.Agent.StepCompletionAction]::QuitWithSuccess
$jbstp.OnFailAction = [Microsoft.SqlServer.Management.Smo.Agent.StepCompletionAction]::QuitWithFailure
$jbstp.Create()
$jb.ApplyToTargetServer($srv.Name)
$jb.IsEnabled = $TRUE
$jb.Start()
請參閱
參考
Microsoft.SqlServer.Management.Smo.Agent 命名空間