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'type' : this class has a finalizer 'finalizer' but no destructor 'dtor'
Remarks
The presence of a finalizer in a type implies resources to delete. Unless a finalizer is explicitly called from the type's destructor, the common language runtime determines when to run the finalizer, after your object goes out of scope.
If you define a destructor in the type and explicitly call the finalizer from the destructor, you can deterministically run your finalizer.
For more information, see Destructors and finalizers.
Example
The following example generates C4461.
// C4461.cpp
// compile with: /W1 /clr /c
ref class A {
protected:
!A() {} // C4461
};
// OK
ref struct B {
~B() {
B::!B();
}
!B() {}
};