DynamicMethod.DeclaringType Property
Definition
Important
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Gets the type that declares the method, which is always null
for dynamic methods.
public:
virtual property Type ^ DeclaringType { Type ^ get(); };
public override Type? DeclaringType { get; }
public override Type DeclaringType { get; }
member this.DeclaringType : Type
Public Overrides ReadOnly Property DeclaringType As Type
Property Value
Always null
.
Examples
The following code example displays the declaring type of a dynamic method. This code example is part of a larger example provided for the DynamicMethod class.
// Display the declaring type, which is always null for dynamic
// methods.
if (hello->DeclaringType == nullptr)
{
Console::WriteLine("\r\nDeclaringType is always null for dynamic methods.");
}
else
{
Console::WriteLine("DeclaringType: {0}", hello->DeclaringType);
}
// Display the declaring type, which is always null for dynamic
// methods.
if (hello.DeclaringType == null)
{
Console.WriteLine("\r\nDeclaringType is always null for dynamic methods.");
}
else
{
Console.WriteLine("DeclaringType: {0}", hello.DeclaringType);
}
' Display the declaring type, which is always Nothing for dynamic
' methods.
If hello.DeclaringType Is Nothing Then
Console.WriteLine(vbCrLf & "DeclaringType is always Nothing for dynamic methods.")
Else
Console.WriteLine("DeclaringType: {0}", hello.DeclaringType)
End If
Remarks
This property always returns null
for dynamic methods. Even when a dynamic method is logically associated with a type, it is not declared by the type.
Applies to
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