Freigeben über


UserControl.Session Eigenschaft

Definition

Ruft das HttpSessionState-Objekt für die aktuelle Webanforderung ab.

public:
 property System::Web::SessionState::HttpSessionState ^ Session { System::Web::SessionState::HttpSessionState ^ get(); };
[System.ComponentModel.Browsable(false)]
public System.Web.SessionState.HttpSessionState Session { get; }
[<System.ComponentModel.Browsable(false)>]
member this.Session : System.Web.SessionState.HttpSessionState
Public ReadOnly Property Session As HttpSessionState

Eigenschaftswert

HttpSessionState

Ein HttpSessionState-Objekt, das der Page zugeordnet ist, die die UserControl-Instanz enthält.

Attribute

Beispiele

Im folgenden Beispiel werden der Session Eigenschaft eines Benutzersteuerelements Werte hinzugefügt. Die myControl.Session.Add Syntax fügt die Werte zweier TextBox Webserversteuerelemente in die Sitzung ein, die dem Benutzersteuerelement und der Seite zugeordnet ist, die sie enthält.

// Save state information which is used by display handler after the postback has occurred.
void SubmitBtn_Click(Object sender, EventArgs e) 
{
  // Clear all values from session state of 'Page'.
  Session.Clear();

  // Populate Session State of UserControl with the values entered by user.
  myControl.Session.Add("username",myControl.user.Text);
  myControl.Session.Add("password",myControl.password.Text);

  // Add UserControl state to the SessionState object of Page.
  Session[myControl.user.Text]= myControl;
  display.Enabled = true;
}

void Display_Click(Object sender, EventArgs e)
{
  int position = Session.Count - 1;

  // Extract stored UserControl from the session state of page.
  LogOnControl tempControl = (LogOnControl)Session[Session.Keys[position]];

  // Use SessionState of UserControl to display previously typed information.
  txtSession.Text = "<br /><br />User:" + tempControl.Session["username"] + "<br />Password : " + tempControl.Session["password"];
  display.Enabled = false;
}
' Saves state information which is used by display handler after the postback has occurred.

Sub SubmitBtn_Click(Sender As Object, e As EventArgs) 

    ' Clear all values from session state of 'Page'.
    Session.Clear()

    ' Populate Session State of UserControl with the values entered by user.
    myControl.Session.Add("username",myControl.user.Text)
    myControl.Session.Add("password",myControl.password.Text)

    ' Add UserControl state to the SessionState object of Page.
    Session(myControl.user.Text)= myControl
    Display.Enabled = true
End Sub

Sub Display_Click(Sender As Object,e As EventArgs)

    Dim position As Integer = Session.Count - 1

    ' Extract stored UserControl from the session state of page.
    Dim tempControl As LogOnControl = CType(Session(Session.Keys(position)),LogOnControl)

    ' Use SessionState of UserControl to display previously typed information.
    txtSession.Text = "<br /><br />User:" + tempControl.Session("username") + "<br />Password : " + tempControl.Session("password")
    Display.Enabled = false
End Sub

Gilt für

Siehe auch