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FontDialog.ShowApply Property

Definition

Gets or sets a value indicating whether the dialog box contains an Apply button.

public:
 property bool ShowApply { bool get(); void set(bool value); };
public bool ShowApply { get; set; }
member this.ShowApply : bool with get, set
Public Property ShowApply As Boolean

Property Value

true if the dialog box contains an Apply button; otherwise, false. The default value is false.

Examples

The following code example shows how to apply the selections in a FontDialog to the text in a RichTextBox. In the event handler that displays the dialog box, the example initializes the ShowApply property to true and then displays the FontDialog. In the Apply event handler, the Font property is assigned to the Control.Font property.

private:
   void button1_Click( Object^ /*sender*/, System::EventArgs^ /*e*/ )
   {
      // Sets the ShowApply property, then displays the dialog.
      fontDialog1->ShowApply = true;
      fontDialog1->ShowDialog();
   }

   void fontDialog1_Apply( Object^ /*sender*/, System::EventArgs^ /*e*/ )
   {
      // Applies the selected font to the selected text.
      richTextBox1->Font = fontDialog1->Font;
   }

private void button1_Click(object sender, System.EventArgs e)
{
    // Sets the ShowApply property, then displays the dialog.

    fontDialog1.ShowApply = true;
    fontDialog1.ShowDialog();
}

private void fontDialog1_Apply(object sender, System.EventArgs e)
{
    // Applies the selected font to the selected text.
    richTextBox1.Font = fontDialog1.Font;
}
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

    ' Sets the ShowApply property, then displays the dialog.
    FontDialog1.ShowApply = True
    FontDialog1.ShowDialog()

End Sub

Private Sub FontDialog1_Apply(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles FontDialog1.Apply

    ' Applies the selected font to the selected text.
    RichTextBox1.SelectionFont = FontDialog1.Font

End Sub

Applies to

See also