HashSet<T>.Remove(T) Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Removes the specified element from a HashSet<T> object.
public:
virtual bool Remove(T item);
public bool Remove (T item);
abstract member Remove : 'T -> bool
override this.Remove : 'T -> bool
Public Function Remove (item As T) As Boolean
Parameters
- item
- T
The element to remove.
Returns
true
if the element is successfully found and removed; otherwise, false
. This method returns false
if item
is not found in the HashSet<T> object.
Implements
Examples
The following example demonstrates how to remove values from a HashSet<T> collection using the Remove method. In this example, zero is arbitrarily removed from the HashSet<T> collection.
HashSet<int> numbers = new HashSet<int>();
for (int i = 0; i < 20; i++) {
numbers.Add(i);
}
// Display all the numbers in the hash table.
Console.Write("numbers contains {0} elements: ", numbers.Count);
DisplaySet(numbers);
// Remove all odd numbers.
numbers.RemoveWhere(IsOdd);
Console.Write("numbers contains {0} elements: ", numbers.Count);
DisplaySet(numbers);
// Check if the hash table contains 0 and, if so, remove it.
if (numbers.Contains(0)) {
numbers.Remove(0);
}
Console.Write("numbers contains {0} elements: ", numbers.Count);
DisplaySet(numbers);
bool IsOdd(int i)
{
return ((i % 2) == 1);
}
void DisplaySet(HashSet<int> set)
{
Console.Write("{");
foreach (int i in set)
Console.Write(" {0}", i);
Console.WriteLine(" }");
}
// This example displays the following output:
// numbers contains 20 elements: { 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 }
// numbers contains 10 elements: { 0 2 4 6 8 10 12 14 16 18 }
// numbers contains 9 elements: { 2 4 6 8 10 12 14 16 18 }
let isOdd i = i % 2 = 1
let displaySet (set: HashSet<int>) =
printf "{"
for i in set do
printf $" {i}"
printfn " }"
let numbers = HashSet<int>()
for i in 1..20 do
numbers.Add i |> ignore
// Display all the numbers in the hash table.
printf $"numbers contains {numbers.Count} elements: "
displaySet numbers
// Remove all odd numbers.
numbers.RemoveWhere isOdd |> ignore
printf $"numbers contains {numbers.Count} elements: "
displaySet numbers
// Check if the hash table contains 0 and, if so, remove it.
if numbers.Contains 0 then
numbers.Remove 0 |> ignore
printf $"numbers contains {numbers.Count} elements: "
displaySet numbers
// This example displays the following output:
// numbers contains 20 elements: { 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 }
// numbers contains 10 elements: { 0 2 4 6 8 10 12 14 16 18 }
// numbers contains 9 elements: { 2 4 6 8 10 12 14 16 18 }
Imports System.Collections.Generic
Module Example
Public Sub Main()
Dim numbers As New HashSet(Of Integer)()
For i As Integer = 0 To 19
numbers.Add(i)
Next i
' Display all the numbers in the hash table.
Console.Write("numbers contains {0} elements: ", numbers.Count)
DisplaySet(numbers)
' Remove all odd numbers.
numbers.RemoveWhere(AddressOf IsOdd)
Console.Write("numbers contains {0} elements: ", numbers.Count)
DisplaySet(numbers)
' Check if the hash table contains 0 and, if so, remove it.
If numbers.Contains(0) Then
numbers.Remove(0)
End If
Console.Write("numbers contains {0} elements: ", numbers.Count)
DisplaySet(numbers)
End Sub
Private Function IsOdd(ByVal i As Integer) As Boolean
Return ((i Mod 2) = 1)
End Function
Private Sub DisplaySet(ByVal coll As HashSet(Of Integer))
Console.Write("{")
For Each i As Integer In coll
Console.Write(" {0}", i)
Next
Console.WriteLine(" }")
End Sub
End Module
' The example displays the following output:
' numbers contains 20 elements: { 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 }
' numbers contains 10 elements: { 0 2 4 6 8 10 12 14 16 18 }
' numbers contains 9 elements: { 2 4 6 8 10 12 14 16 18 }
Remarks
If the HashSet<T> object does not contain the specified element, the object remains unchanged. No exception is thrown.
This method is an O(1) operation.