ContextMenu.IsOpen Property

Reference

Definition

Namespace:: System.Windows.Controls

Assembly:: PresentationFramework.dll

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Gets or sets a value that indicates whether the ContextMenu is visible.

public:
 property bool IsOpen { bool get(); void set(bool value); };

[System.ComponentModel.Bindable(true)]
[System.ComponentModel.Browsable(false)]
public bool IsOpen { get; set; }

[<System.ComponentModel.Bindable(true)>]
[<System.ComponentModel.Browsable(false)>]
member this.IsOpen : bool with get, set

Public Property IsOpen As Boolean

Property Value

Boolean

true if the ContextMenu is visible; otherwise, false. The default is false.

Attributes: BindableAttribute BrowsableAttribute

Examples

This example shows how to check to determine whether the IsOpen property is set to true.

if (cm.IsOpen)
{
    cmButton.Content = "The ContextMenu opened and the IsOpen property is true.";
}

If cm.IsOpen = True Then
    cmButton.Content = "The ContextMenu opened and the IsOpen property is true."
End If

Remarks

When IsOpen is set to true, mouse capture is set to the ContextMenu and its subtree.

Dependency Property Information

Item	Value
Identifier field	IsOpenProperty
Metadata properties set to `true`	BindsTwoWayByDefault

Applies to

Product	Versions
.NET Framework	3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop	3.0, 3.1, 5, 6, 7, 8, 9, 10

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