Queryable.Last Method
Definition
Important
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Returns the last element in a sequence.
Overloads
Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>) |
Returns the last element of a sequence that satisfies a specified condition. |
Last<TSource>(IQueryable<TSource>) |
Returns the last element in a sequence. |
Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>)
- Source:
- Queryable.cs
- Source:
- Queryable.cs
- Source:
- Queryable.cs
Returns the last element of a sequence that satisfies a specified condition.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static TSource Last(System::Linq::IQueryable<TSource> ^ source, System::Linq::Expressions::Expression<Func<TSource, bool> ^> ^ predicate);
public static TSource Last<TSource> (this System.Linq.IQueryable<TSource> source, System.Linq.Expressions.Expression<Func<TSource,bool>> predicate);
static member Last : System.Linq.IQueryable<'Source> * System.Linq.Expressions.Expression<Func<'Source, bool>> -> 'Source
<Extension()>
Public Function Last(Of TSource) (source As IQueryable(Of TSource), predicate As Expression(Of Func(Of TSource, Boolean))) As TSource
Type Parameters
- TSource
The type of the elements of source
.
Parameters
- source
- IQueryable<TSource>
An IQueryable<T> to return an element from.
- predicate
- Expression<Func<TSource,Boolean>>
A function to test each element for a condition.
Returns
The last element in source
that passes the test specified by predicate
.
Exceptions
source
or predicate
is null
.
No element satisfies the condition in predicate
.
-or-
The source sequence is empty.
Examples
The following code example demonstrates how to use Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>) to return the last element of an array that satisfies a condition.
int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54,
83, 23, 87, 67, 12, 19 };
// Get the last number in the array that is greater than 80.
int last = numbers.AsQueryable().Last(num => num > 80);
Console.WriteLine(last);
/*
This code produces the following output:
87
*/
Dim numbers() As Integer = {9, 34, 65, 92, 87, 435, 3, 54, _
83, 23, 87, 67, 12, 19}
' Get the last number in the array that is greater than 80.
Dim last As Integer = numbers.AsQueryable().Last(Function(num) num > 80)
MsgBox(last)
' This code produces the following output:
' 87
Remarks
This method has at least one parameter of type Expression<TDelegate> whose type argument is one of the Func<T,TResult> types. For these parameters, you can pass in a lambda expression and it will be compiled to an Expression<TDelegate>.
The Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>) method generates a MethodCallExpression that represents calling Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>) itself as a constructed generic method. It then passes the MethodCallExpression to the Execute<TResult>(Expression) method of the IQueryProvider represented by the Provider property of the source
parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Last<TSource>(IQueryable<TSource>, Expression<Func<TSource,Boolean>>) depends on the implementation of the type of the source
parameter. The expected behavior is that it returns the last element in source
that satisfies the condition specified by predicate
.
Applies to
Last<TSource>(IQueryable<TSource>)
- Source:
- Queryable.cs
- Source:
- Queryable.cs
- Source:
- Queryable.cs
Returns the last element in a sequence.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static TSource Last(System::Linq::IQueryable<TSource> ^ source);
public static TSource Last<TSource> (this System.Linq.IQueryable<TSource> source);
static member Last : System.Linq.IQueryable<'Source> -> 'Source
<Extension()>
Public Function Last(Of TSource) (source As IQueryable(Of TSource)) As TSource
Type Parameters
- TSource
The type of the elements of source
.
Parameters
- source
- IQueryable<TSource>
An IQueryable<T> to return the last element of.
Returns
The value at the last position in source
.
Exceptions
source
is null
.
The source sequence is empty.
Examples
The following code example demonstrates how to use Last<TSource>(IQueryable<TSource>) to return the last element of an array.
int[] numbers = { 9, 34, 65, 92, 87, 435, 3, 54,
83, 23, 87, 67, 12, 19 };
int last = numbers.AsQueryable().Last();
Console.WriteLine(last);
/*
This code produces the following output:
19
*/
Dim numbers() As Integer = {9, 34, 65, 92, 87, 435, 3, 54, _
83, 23, 87, 67, 12, 19}
Dim last As Integer = numbers.AsQueryable().Last()
MsgBox(last)
' This code produces the following output:
' 19
Remarks
The Last<TSource>(IQueryable<TSource>) method generates a MethodCallExpression that represents calling Last<TSource>(IQueryable<TSource>) itself as a constructed generic method. It then passes the MethodCallExpression to the Execute<TResult>(Expression) method of the IQueryProvider represented by the Provider property of the source
parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Last<TSource>(IQueryable<TSource>) depends on the implementation of the type of the source
parameter. The expected behavior is that it returns the last element in source
.