PropertyBuilder<TProperty>.HasPrecision Method
Definition
Important
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Overloads
| HasPrecision(Int32) |
Configures the precision of the property. |
| HasPrecision(Int32, Int32) |
Configures the precision and scale of the property. |
HasPrecision(Int32)
Configures the precision of the property.
public virtual Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<TProperty> HasPrecision (int precision);override this.HasPrecision : int -> Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<'Property>Public Overridable Function HasPrecision (precision As Integer) As PropertyBuilder(Of TProperty)Parameters
- precision
- Int32
The precision of the property.
Returns
The same builder instance so that multiple configuration calls can be chained.
Applies to
HasPrecision(Int32, Int32)
Configures the precision and scale of the property.
public virtual Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<TProperty> HasPrecision (int precision, int scale);override this.HasPrecision : int * int -> Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<'Property>Public Overridable Function HasPrecision (precision As Integer, scale As Integer) As PropertyBuilder(Of TProperty)Parameters
- precision
- Int32
The precision of the property.
- scale
- Int32
The scale of the property.
Returns
The same builder instance so that multiple configuration calls can be chained.
Applies to
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Entity Framework