Expression.Decrement Method
Definition
Important
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Creates a UnaryExpression that represents the decrementing of the expression by 1.
Overloads
Decrement(Expression) |
Creates a UnaryExpression that represents the decrementing of the expression by 1. |
Decrement(Expression, MethodInfo) |
Creates a UnaryExpression that represents the decrementing of the expression by 1. |
Decrement(Expression)
- Source:
- UnaryExpression.cs
- Source:
- UnaryExpression.cs
- Source:
- UnaryExpression.cs
Creates a UnaryExpression that represents the decrementing of the expression by 1.
public:
static System::Linq::Expressions::UnaryExpression ^ Decrement(System::Linq::Expressions::Expression ^ expression);
public static System.Linq.Expressions.UnaryExpression Decrement (System.Linq.Expressions.Expression expression);
static member Decrement : System.Linq.Expressions.Expression -> System.Linq.Expressions.UnaryExpression
Public Shared Function Decrement (expression As Expression) As UnaryExpression
Parameters
- expression
- Expression
An Expression to decrement.
Returns
A UnaryExpression that represents the decremented expression.
Examples
The following code example shows how to create an expression that subtracts 1 from a given value.
// Add the following directive to your file:
// using System.Linq.Expressions;
double num = 5.5;
// This expression represents a decrement operation
// that subtracts 1 from a value.
Expression decrementExpr = Expression.Decrement(
Expression.Constant(num)
);
// Print expression.
Console.WriteLine(decrementExpr.ToString());
// The following statement first creates an expression tree,
// then compiles it, and then executes it.
Console.WriteLine(
Expression.Lambda<Func<double>>(decrementExpr).Compile()());
// The value of the variable did not change,
// because the expression is functional.
Console.WriteLine("object: " + num);
// This code example produces the following output:
//
// Decrement(5.5)
// 4.5
// object: 5.5
' Add the following directive to your file:
' Imports System.Linq.Expressions
Dim num As Double = 5.5
' This expression represents a decrement operation
' that subtracts 1 from a value.
Dim decrementExpr As Expression = Expression.Decrement(
Expression.Constant(num)
)
' Print the expression.
Console.WriteLine(decrementExpr.ToString())
' The following statement first creates an expression tree,
' then compiles it, and then executes it.
Console.WriteLine(
Expression.Lambda(Of Func(Of Double))(decrementExpr).Compile()())
' The value of the variable did not change,
' because the expression is functional.
Console.WriteLine("object: " & num)
' This code example produces the following output:
'
' Decrement(5.5)
' 4.5
' object: 5.5
Remarks
This expression is functional and does not change the value of the object passed to it.
Applies to
Decrement(Expression, MethodInfo)
- Source:
- UnaryExpression.cs
- Source:
- UnaryExpression.cs
- Source:
- UnaryExpression.cs
Creates a UnaryExpression that represents the decrementing of the expression by 1.
public:
static System::Linq::Expressions::UnaryExpression ^ Decrement(System::Linq::Expressions::Expression ^ expression, System::Reflection::MethodInfo ^ method);
public static System.Linq.Expressions.UnaryExpression Decrement (System.Linq.Expressions.Expression expression, System.Reflection.MethodInfo method);
public static System.Linq.Expressions.UnaryExpression Decrement (System.Linq.Expressions.Expression expression, System.Reflection.MethodInfo? method);
static member Decrement : System.Linq.Expressions.Expression * System.Reflection.MethodInfo -> System.Linq.Expressions.UnaryExpression
Public Shared Function Decrement (expression As Expression, method As MethodInfo) As UnaryExpression
Parameters
- expression
- Expression
An Expression to decrement.
- method
- MethodInfo
A MethodInfo that represents the implementing method.
Returns
A UnaryExpression that represents the decremented expression.
Remarks
This expression is functional and does not change the value of the object passed to it.