Is there a way to get rid of any duplicates that it may have in it ( example 234 234)
I assume you mean the digits 2-3-4 would be in three separate, adjacent columns, not simply somewhere arbitrarily in the long string of digits, correct? I do not believe that would be possible using formulas (or, if it is possible, such a formula would be
large and ugly); however, it can be done using VBA code, but such code would replace the formula method completely. If you absolutely need such functionality, and if you can make use of VBA code in your workbook, let me know and I will try to develop such
a VBA solution for you.
Rick,
These are my steps that I take and what ever I can do within a Macro would be FANTASTIC because it is very time consuming to copy and paste all the data and sort it into columns and rows. If you look at the very first post I start with 881
1) Paste the data in B:2 881.431009727919581624773191062370305904717895794684262693389860231776157431507154828780520474137937454600348884547522061........
2) Take the left end single digit (the bold 8) cut it and paste it to the far right end and then paste the new number and remove decimal point between the 1 and 4 (814310097279195816247731910623703059047178957946842626933898602317761574315071548287805204741379374546003488845475220618)
string in B:4
3) Take the new far left digit which happens to be another 8 (in bold) and cut it and paste it to the far right end and then paste the new number (14310097279195816247731910623703059047178957946842626933898602317761574315071548287805204741379374546003488845475220618 8)
string in B:6
Then I would put them in their own cell like we are doing now. After I do that I break them up into 3x3 cubes or 3x4 cubes and get rid of any duplicates that may be in the set of 3 or 4 digits in any combination. The 3x3 will have 9 digits and the 3x4
will have 12 digits If a row has 1234 and another has 4231 I delete one of them.
What ever steps I can get help with in a Macro is much appreciated to save a lot of time
Thanks
