Error value in field after derive transformation

Question

I am trying to get the unsigned value of a signed integer in a derive transformation for column with numeric values with the following

toInteger(iif(toInteger($$)<0, power(2, 32),toDouble(0))+toDouble($$))

I am getting an internal error - all negative values get the value '2147483647'

What can be the issue here?

Answer 1

Are you looking for absolute value? abs() ?

Answer 2

no. for example, i am trying the get the unsigned value of -20, which is not 20 (abs) but -20+2^32
i think i get some overflow internally at that procedure but it is not clear why.

the 2147483647 i get is kind of generic error value

Answer 3

Hello @Kobi Averbuch ,

Thanks for the question and using MS Q&A platform.

I checked your expression - I checking the output at the level

iif(toInteger($$)<0, power(2, 32),toDouble(0))+toDouble($$)  

I was getting the number in the in the scientific format. number-E-x

4.294967276E9  

From research, currently toInteger cannot handle scientific format of numbers.

I did modify the expression and i got a simlar output at my end.

So I came up with the below expression that gives the required output

toDecimal(iif(toInteger(-20)<0, toDecimal(power(2, 32),12),toDecimal(0))+toDecimal(-20),12,0)  

I have used -20 for illustration but you can replace it at your end.

Output:

-20+2^32= 4294967276

Note :

Integer Range is between : -2147483648 to 2147483647.
Unsigned integer range would be between 0 to 4294967295

You may not be able to use the toInteger(<iif.....>)

Hope this will help. Please let us know if any further queries.

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