remove values from string

Shambhu Rai 1,411 Reputation points
2022-08-17T10:50:23.187+00:00

Hi Expert,

how will i remove all the characters from values in sql

Create table test1
(id string, details string)

insert into test1
values('20kjk','3ddf')

Regards

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Accepted answer
  1. Yitzhak Khabinsky 25,956 Reputation points
    2022-08-17T12:58:16.167+00:00

    Hi @Shambhu Rai ,

    Please try the following solution. It will work starting from SQL Server 2017 onwards.

    SQL

    -- DDL and sample data population, start  
    DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, details VARCHAR(100));  
    INSERT INTO @tbl values   
    ('20kjk'),  
    ('3ddf'),  
    ('561.456/.7890');  
    -- DDL and sample data population, end  
      
    -- SQL Server 2017 onwards  
    ;WITH rs AS   
    (  
       SELECT *  
          , REPLACE(TRANSLATE(details, '0123456789', SPACE(10)),' ','') AS JunkCharacters  
       FROM @tbl  
    )  
    SELECT rs.*  
       , REPLACE(TRANSLATE(details, TRIM(JunkCharacters), SPACE(LEN(TRIM(JunkCharacters)))),' ','') AS CleansedDetails  
    FROM rs;  
    

    Output

    +----+---------------+----------------+-----------------+  
    | ID |    details    | JunkCharacters | CleansedDetails |  
    +----+---------------+----------------+-----------------+  
    |  1 | 20kjk         | kjk            |              20 |  
    |  2 | 3ddf          | ddf            |               3 |  
    |  3 | 561.456/.7890 | ./.            |      5614567890 |  
    +----+---------------+----------------+-----------------+  
    
    1 person found this answer helpful.
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5 additional answers

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  1. Ebrahim Bazarjani 5 Reputation points
    2024-05-11T10:29:32.2366667+00:00

    Hi,

    You can Use This :

    CREATE FUNCTION udfFG_GetNumFromStr (@Str VARCHAR(64))
    RETURNS VARCHAR(64)
    AS
    BEGIN
    	DECLARE @Pos int,@Char char(1)
    	SET @Pos = PATINDEX('%[^0-9]%',@Str)
    	WHILE @Pos > 0
    	BEGIN
    		SET @Char = SUBSTRING(@Str,@Pos,1)
    		SET @Str = REPLACE(@Str,@Char,'')
    		SET @Pos = PATINDEX('%[^0-9]%',@Str)
    	END
    RETURN @Str
    END
    
    0 comments No comments

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