Uri.SchemeDelimiter Field
Definition
Important
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Specifies the characters that separate the communication protocol scheme from the address portion of the URI. This field is read-only.
public: static initonly System::String ^ SchemeDelimiter;
public static readonly string SchemeDelimiter;
staticval mutable SchemeDelimiter : string
Public Shared ReadOnly SchemeDelimiter As String
Field Value
Examples
The following example creates a string from UriSchemeHttp, SchemeDelimiter, and an address. A Uri instance is then created from the string.
String^ address = "www.contoso.com";
String^ uriString = String::Format( "{0}{1}{2}",
Uri::UriSchemeHttp, Uri::SchemeDelimiter, address );
#if OLDMETHOD
Uri^ result;
if ( Uri::TryParse( uriString, false, false, result ) == true )
{
Console::WriteLine( "{0} is a valid Uri", result );
}
else
{
Console::WriteLine( "Uri not created" );
}
#endif
Uri ^result = gcnew Uri(uriString);
if (result->IsWellFormedOriginalString())
Console::WriteLine("{0} is a well formed Uri", uriString);
else
Console::WriteLine("{0} is not a well formed Uri", uriString);
string address = "www.contoso.com";
string uriString = String.Format("{0}{1}{2}/", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address);
#if OLDMETHOD
Uri result;
if (Uri.TryParse(uriString, false, false, out result) == true)
Console.WriteLine("{0} is a valid Uri", result.ToString());
else
Console.WriteLine("Uri not created");
#endif
Uri result = new Uri(uriString);
if (result.IsWellFormedOriginalString())
Console.WriteLine("{0} is a well formed Uri", uriString);
else
Console.WriteLine("{0} is not a well formed Uri", uriString);
let address = "www.contoso.com"
let uriString = $"{Uri.UriSchemeHttp}{Uri.SchemeDelimiter}{address}/"
#if OLDMETHOD
match Uri.TryParse(uriString, false, false) with
| true, result ->
printfn $"{result} is a valid Uri"
| _ ->
printfn "Uri not created"
#endif
let result = Uri uriString
if result.IsWellFormedOriginalString() then
printfn $"{uriString} is a well formed Uri"
else
printfn $"{uriString} is not a well formed Uri"
Dim address As String = "www.contoso.com"
Dim uriString As String = String.Format("{0}{1}{2}", Uri.UriSchemeHttp, Uri.SchemeDelimiter, address)
Dim result As Uri = New Uri(uriString)
If result.IsWellFormedOriginalString() = True Then
Console.WriteLine("{0} is a well formed Uri", uriString)
else
Console.WriteLine("{0} is not a well formed Uri", uriString)
End If
Applies to
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