IfDirectiveTriviaSyntax.WithIfKeyword(SyntaxToken) Method
Definition
Important
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public:
Microsoft::CodeAnalysis::CSharp::Syntax::IfDirectiveTriviaSyntax ^ WithIfKeyword(Microsoft::CodeAnalysis::SyntaxToken ifKeyword);public Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntax WithIfKeyword (Microsoft.CodeAnalysis.SyntaxToken ifKeyword);member this.WithIfKeyword : Microsoft.CodeAnalysis.SyntaxToken -> Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntaxPublic Function WithIfKeyword (ifKeyword As SyntaxToken) As IfDirectiveTriviaSyntaxParameters
- ifKeyword
- SyntaxToken
Returns
Applies to
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