Color.Inequality(Color, Color) Operator
Definition
Important
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Tests whether two specified Color structures are different.
public:
static bool operator !=(System::Drawing::Color left, System::Drawing::Color right);
public static bool operator != (System.Drawing.Color left, System.Drawing.Color right);
static member op_Inequality : System.Drawing.Color * System.Drawing.Color -> bool
Public Shared Operator != (left As Color, right As Color) As Boolean
Parameters
Returns
true
if the two Color structures are different; otherwise, false
.
Examples
The following code example demonstrates the Inequality operator and the SystemColors class. This example is designed to be used with a Windows Form that contains a button named Button2
. Paste the following code into your form and associate the Button2_Click
method with the button's Click event.
void Button2_Click( System::Object^ /*sender*/, System::EventArgs^ /*e*/ )
{
if ( this->BackColor != SystemColors::ControlDark )
{
this->BackColor = SystemColors::ControlDark;
}
if ( !(this->Font->Bold) )
{
this->Font = gcnew System::Drawing::Font( this->Font,FontStyle::Bold );
}
}
private void Button2_Click(System.Object sender, System.EventArgs e)
{
if (this.BackColor != SystemColors.ControlDark)
{
this.BackColor = SystemColors.ControlDark;
}
if (!(this.Font.Bold))
{
this.Font = new Font(this.Font, FontStyle.Bold);
}
}
Private Sub Button2_Click(ByVal sender As System.Object, _
ByVal e As System.EventArgs) Handles Button2.Click
If (Color.op_Inequality(Me.BackColor, SystemColors.ControlDark)) Then
Me.BackColor = SystemColors.ControlDark
End If
If Not (Me.Font.Bold) Then
Me.Font = New Font(Me.Font, FontStyle.Bold)
End If
End Sub
Remarks
This method compares more than the ARGB values of the Color structures. It also does a comparison of some state flags. If you want to compare just the ARGB values of two Color structures, use the ToArgb method.