Enumerable.Sum Method

Definition

Computes the sum of a sequence of numeric values.

Overloads

Sum(IEnumerable<Single>)

Computes the sum of a sequence of Single values.

Sum(IEnumerable<Nullable<Int32>>)

Computes the sum of a sequence of nullable Int32 values.

Sum(IEnumerable<Nullable<Single>>)

Computes the sum of a sequence of nullable Single values.

Sum(IEnumerable<Nullable<Int64>>)

Computes the sum of a sequence of nullable Int64 values.

Sum(IEnumerable<Nullable<Double>>)

Computes the sum of a sequence of nullable Double values.

Sum(IEnumerable<Int32>)

Computes the sum of a sequence of Int32 values.

Sum(IEnumerable<Int64>)

Computes the sum of a sequence of Int64 values.

Sum(IEnumerable<Double>)

Computes the sum of a sequence of Double values.

Sum(IEnumerable<Decimal>)

Computes the sum of a sequence of Decimal values.

Sum(IEnumerable<Nullable<Decimal>>)

Computes the sum of a sequence of nullable Decimal values.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

Sum(IEnumerable<Single>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of Single values.

C#
public static float Sum(this System.Collections.Generic.IEnumerable<float> source);

Parameters

source
IEnumerable<Single>

A sequence of Single values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

Examples

The following code example demonstrates how to use Sum(IEnumerable<Single>) to sum the values of a sequence.

C#
List<float> numbers = new List<float> { 43.68F, 1.25F, 583.7F, 6.5F };

float sum = numbers.Sum();

Console.WriteLine("The sum of the numbers is {0}.", sum);

/*
 This code produces the following output:

 The sum of the numbers is 635.13.
*/

Remarks

This method returns zero if source contains no elements.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Nullable<Int32>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of nullable Int32 values.

C#
public static int? Sum(this System.Collections.Generic.IEnumerable<int?> source);

Parameters

source
IEnumerable<Nullable<Int32>>

A sequence of nullable Int32 values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Int32.MaxValue.

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Nullable<Single>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of nullable Single values.

C#
public static float? Sum(this System.Collections.Generic.IEnumerable<float?> source);

Parameters

source
IEnumerable<Nullable<Single>>

A sequence of nullable Single values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

Examples

The following code example demonstrates how to use Sum(IEnumerable<Nullable<Single>>) to sum the values of a sequence.

C#
float?[] points = { null, 0, 92.83F, null, 100.0F, 37.46F, 81.1F };

float? sum = points.Sum();

Console.WriteLine("Total points earned: {0}", sum);

/*
 This code produces the following output:

 Total points earned: 311.39
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Nullable<Int64>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of nullable Int64 values.

C#
public static long? Sum(this System.Collections.Generic.IEnumerable<long?> source);

Parameters

source
IEnumerable<Nullable<Int64>>

A sequence of nullable Int64 values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Int64.MaxValue.

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Nullable<Double>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of nullable Double values.

C#
public static double? Sum(this System.Collections.Generic.IEnumerable<double?> source);

Parameters

source
IEnumerable<Nullable<Double>>

A sequence of nullable Double values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Double.MaxValue.

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Int32>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of Int32 values.

C#
public static int Sum(this System.Collections.Generic.IEnumerable<int> source);

Parameters

source
IEnumerable<Int32>

A sequence of Int32 values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Int32.MaxValue.

Remarks

This method returns zero if source contains no elements.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Int64>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of Int64 values.

C#
public static long Sum(this System.Collections.Generic.IEnumerable<long> source);

Parameters

source
IEnumerable<Int64>

A sequence of Int64 values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Int64.MaxValue.

Remarks

This method returns zero if source contains no elements.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Double>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of Double values.

C#
public static double Sum(this System.Collections.Generic.IEnumerable<double> source);

Parameters

source
IEnumerable<Double>

A sequence of Double values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Double.MaxValue.

Remarks

This method returns zero if source contains no elements.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Decimal>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of Decimal values.

C#
public static decimal Sum(this System.Collections.Generic.IEnumerable<decimal> source);

Parameters

source
IEnumerable<Decimal>

A sequence of Decimal values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Decimal.MaxValue.

Remarks

The Sum(IEnumerable<Decimal>) method returns zero if source contains no elements.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum(IEnumerable<Nullable<Decimal>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of a sequence of nullable Decimal values.

C#
public static decimal? Sum(this System.Collections.Generic.IEnumerable<decimal?> source);

Parameters

source
IEnumerable<Nullable<Decimal>>

A sequence of nullable Decimal values to calculate the sum of.

Returns

The sum of the values in the sequence.

Exceptions

source is null.

The sum is larger than Decimal.MaxValue.

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of Single values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static float Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Single>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

The Sum<TSource>(IEnumerable<TSource>, Func<TSource,Single>) method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Single.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int64>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of nullable Int64 values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static long? Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long?> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int64>>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Int64.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int64> in C# or Nullable(Of Int64) in Visual Basic

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Int32>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of nullable Int32 values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static int? Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int?> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Int32>>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Int32.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Int32> in C# or Nullable(Of Int32) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Double>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of nullable Double values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static double? Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double?> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Double>>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Double.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Double> in C# or Nullable(Of Double) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Single>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of nullable Single values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static float? Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,float?> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Single>>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Single> in C# or Nullable(Of Single) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int64>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of Int64 values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static long Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,long> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int64>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Int64.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

This method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int64.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Int32>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of Int32 values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static int Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,int> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Int32>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Int32.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

This method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Int32.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of Double values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static double Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,double> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Double>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Double.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

This method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Double.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Decimal>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of Decimal values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static decimal Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Decimal>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Decimal.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

This method returns zero if source contains no elements.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Decimal.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0

Sum<TSource>(IEnumerable<TSource>, Func<TSource,Nullable<Decimal>>)

Source:
Sum.cs
Source:
Sum.cs
Source:
Sum.cs

Computes the sum of the sequence of nullable Decimal values that are obtained by invoking a transform function on each element of the input sequence.

C#
public static decimal? Sum<TSource>(this System.Collections.Generic.IEnumerable<TSource> source, Func<TSource,decimal?> selector);

Type Parameters

TSource

The type of the elements of source.

Parameters

source
IEnumerable<TSource>

A sequence of values that are used to calculate a sum.

selector
Func<TSource,Nullable<Decimal>>

A transform function to apply to each element.

Returns

The sum of the projected values.

Exceptions

source or selector is null.

The sum is larger than Decimal.MaxValue.

Examples

The following code example demonstrates how to use Sum<TSource>(IEnumerable<TSource>, Func<TSource,Double>) to sum the projected values of a sequence.

Note

This code example uses an overload of the method that's different from the specific overload that this article describes. To extend the example to the overload that this article describes, change the body of the selector function.

C#
class Package
{
    public string Company { get; set; }
    public double Weight { get; set; }
}

public static void SumEx1()
{
    List<Package> packages =
        new List<Package>
            { new Package { Company = "Coho Vineyard", Weight = 25.2 },
              new Package { Company = "Lucerne Publishing", Weight = 18.7 },
              new Package { Company = "Wingtip Toys", Weight = 6.0 },
              new Package { Company = "Adventure Works", Weight = 33.8 } };

    double totalWeight = packages.Sum(pkg => pkg.Weight);

    Console.WriteLine("The total weight of the packages is: {0}", totalWeight);
}

/*
 This code produces the following output:

 The total weight of the packages is: 83.7
*/

Remarks

Items in source that are null are excluded from the computation of the sum. This method returns zero if source contains no elements or all elements are null.

You can apply this method to a sequence of arbitrary values if you provide a function, selector, that projects the members of source into a numeric type, specifically Nullable<Decimal> in C# or Nullable(Of Decimal) in Visual Basic.

In Visual Basic query expression syntax, an Aggregate Into Sum() clause translates to an invocation of Sum.

See also

Applies to

.NET 9 and other versions
Product Versions
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.6, 2.0, 2.1
UWP 10.0