Queryable.Max Method
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| Max<TSource,TResult>(IQueryable<TSource>, Expression<Func<TSource,TResult>>) |
Invokes a projection function on each element of a generic IQueryable<T> and returns the maximum resulting value. |
| Max<TSource>(IQueryable<TSource>) |
Returns the maximum value in a generic IQueryable<T>. |
| Max<TSource>(IQueryable<TSource>, IComparer<TSource>) |
Returns the maximum value in a generic IQueryable<T>. |
- Source:
- Queryable.cs
- Source:
- Queryable.cs
- Source:
- Queryable.cs
Invokes a projection function on each element of a generic IQueryable<T> and returns the maximum resulting value.
public:
generic <typename TSource, typename TResult>
[System::Runtime::CompilerServices::Extension]
static TResult Max(System::Linq::IQueryable<TSource> ^ source, System::Linq::Expressions::Expression<Func<TSource, TResult> ^> ^ selector);public static TResult Max<TSource,TResult>(this System.Linq.IQueryable<TSource> source, System.Linq.Expressions.Expression<Func<TSource,TResult>> selector);public static TResult? Max<TSource,TResult>(this System.Linq.IQueryable<TSource> source, System.Linq.Expressions.Expression<Func<TSource,TResult>> selector);static member Max : System.Linq.IQueryable<'Source> * System.Linq.Expressions.Expression<Func<'Source, 'Result>> -> 'Result<Extension()>
Public Function Max(Of TSource, TResult) (source As IQueryable(Of TSource), selector As Expression(Of Func(Of TSource, TResult))) As TResultType Parameters
- TSource
The type of the elements of source.
- TResult
The type of the value returned by the function represented by selector.
Parameters
- source
- IQueryable<TSource>
A sequence of values to determine the maximum of.
- selector
- Expression<Func<TSource,TResult>>
A projection function to apply to each element.
Returns
The maximum value in the sequence.
Exceptions
source or selector is null.
source contains no elements.
Examples
The following code example demonstrates how to use Max<TSource,TResult>(IQueryable<TSource>, Expression<Func<TSource,TResult>>) to determine the maximum value in a sequence of projected values.
class Pet
{
public string Name { get; set; }
public int Age { get; set; }
}
public static void MaxEx2()
{
Pet[] pets = { new Pet { Name="Barley", Age=8 },
new Pet { Name="Boots", Age=4 },
new Pet { Name="Whiskers", Age=1 } };
// Add Pet.Age to the length of Pet.Name
// to determine the "maximum" Pet object in the array.
int max =
pets.AsQueryable().Max(pet => pet.Age + pet.Name.Length);
Console.WriteLine(
"The maximum pet age plus name length is {0}.",
max);
}
/*
This code produces the following output:
The maximum pet age plus name length is 14.
*/
Structure Pet
Public Name As String
Public Age As Integer
End Structure
Shared Sub MaxEx2()
Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8}, _
New Pet With {.Name = "Boots", .Age = 4}, _
New Pet With {.Name = "Whiskers", .Age = 1}}
' Add Pet.Age to the length of Pet.Name
' to determine the "maximum" Pet object in the array.
Dim max As Integer = _
pets.AsQueryable().Max(Function(pet) pet.Age + pet.Name.Length)
MsgBox(String.Format("The maximum pet age plus name length is {0}.", max))
'This code produces the following output:
'The maximum pet age plus name length is 14.
Remarks
This method has at least one parameter of type Expression<TDelegate> whose type argument is one of the Func<T,TResult> types. For these parameters, you can pass in a lambda expression and it will be compiled to an Expression<TDelegate>.
The Max<TSource,TResult>(IQueryable<TSource>, Expression<Func<TSource,TResult>>) method generates a MethodCallExpression that represents calling Max<TSource,TResult>(IQueryable<TSource>, Expression<Func<TSource,TResult>>) itself as a constructed generic method. It then passes the MethodCallExpression to the Execute<TResult>(Expression) method of the IQueryProvider represented by the Provider property of the source parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Max<TSource,TResult>(IQueryable<TSource>, Expression<Func<TSource,TResult>>) depends on the implementation of the type of the source parameter. The expected behavior is that it invokes selector on each element in source and returns the maximum value.
Applies to
.NET 9 and other versions
| Product | Versions |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9 |
| .NET Framework | 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 2.0, 2.1 |
| UWP | 10.0 |
- Source:
- Queryable.cs
- Source:
- Queryable.cs
- Source:
- Queryable.cs
Returns the maximum value in a generic IQueryable<T>.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static TSource Max(System::Linq::IQueryable<TSource> ^ source);public static TSource Max<TSource>(this System.Linq.IQueryable<TSource> source);public static TSource? Max<TSource>(this System.Linq.IQueryable<TSource> source);static member Max : System.Linq.IQueryable<'Source> -> 'Source<Extension()>
Public Function Max(Of TSource) (source As IQueryable(Of TSource)) As TSourceType Parameters
- TSource
The type of the elements of source.
Parameters
- source
- IQueryable<TSource>
A sequence of values to determine the maximum of.
Returns
The maximum value in the sequence.
Exceptions
source is null.
source contains no elements.
Examples
The following code example demonstrates how to use Max<TSource>(IQueryable<TSource>) to determine the maximum value in a sequence.
List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };
long max = longs.AsQueryable().Max();
Console.WriteLine("The largest number is {0}.", max);
/*
This code produces the following output:
The largest number is 4294967296.
*/
Dim longs As New List(Of Long)(New Long() {4294967296L, 466855135L, 81125L})
Dim max As Long = longs.AsQueryable().Max()
MsgBox(String.Format("The largest number is {0}.", max))
'This code produces the following output:
'The largest number is 4294967296.
Remarks
The Max<TSource>(IQueryable<TSource>) method generates a MethodCallExpression that represents calling Max<TSource>(IQueryable<TSource>) itself as a constructed generic method. It then passes the MethodCallExpression to the Execute<TResult>(Expression) method of the IQueryProvider represented by the Provider property of the source parameter.
The query behavior that occurs as a result of executing an expression tree that represents calling Max<TSource>(IQueryable<TSource>) depends on the implementation of the type of the source parameter. The expected behavior is that it returns the maximum value in source.
Applies to
.NET 9 and other versions
| Product | Versions |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9 |
| .NET Framework | 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 2.0, 2.1 |
| UWP | 10.0 |
- Source:
- Queryable.cs
- Source:
- Queryable.cs
- Source:
- Queryable.cs
Returns the maximum value in a generic IQueryable<T>.
public:
generic <typename TSource>
[System::Runtime::CompilerServices::Extension]
static TSource Max(System::Linq::IQueryable<TSource> ^ source, System::Collections::Generic::IComparer<TSource> ^ comparer);public static TSource? Max<TSource>(this System.Linq.IQueryable<TSource> source, System.Collections.Generic.IComparer<TSource>? comparer);static member Max : System.Linq.IQueryable<'Source> * System.Collections.Generic.IComparer<'Source> -> 'Source<Extension()>
Public Function Max(Of TSource) (source As IQueryable(Of TSource), comparer As IComparer(Of TSource)) As TSourceType Parameters
- TSource
The type of the elements of source.
Parameters
- source
- IQueryable<TSource>
A sequence of values to determine the maximum value of.
- comparer
- IComparer<TSource>
The IComparer<T> to compare values.
Returns
The maximum value in the sequence.
Exceptions
source is null.
Applies to
.NET 9 and other versions
| Product | Versions |
|---|---|
| .NET | 6, 7, 8, 9 |
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