DataGridItem.DataItem Property

Definition

Gets or sets the data item represented by the DataGridItem object in the DataGrid control.

C#
public virtual object DataItem { get; set; }

Property Value

A Object that represents a data item in the DataGrid control.

Examples

The following code example demonstrates how to use the DataItem property to display the contents of the data items in the DataGrid control.

Note

The following code example uses the single-file code model and might not work correctly if copied directly into a code-behind file. This code example must be copied into an empty text file that has an .aspx extension.

ASP.NET (C#)
<%@ Page Language="C#" AutoEventWireup="True" %>
<%@ Import Namespace="System.Data" %>
 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" >
<script language="C#" runat="server">
 
   DataTable Cart;
   DataView CartView;
 
   ICollection CreateDataSource() 
   {
      DataTable dt = new DataTable();
      DataRow dr;
 
      dt.Columns.Add(new DataColumn("IntegerValue", typeof(Int32)));
      dt.Columns.Add(new DataColumn("StringValue", typeof(string)));
      dt.Columns.Add(new DataColumn("CurrencyValue", typeof(double)));
 
      for (int i = 0; i < 10; i++) 
      {
         dr = dt.NewRow();
 
         dr[0] = i;
         dr[1] = "Item " + i.ToString();
         dr[2] = 1.23 * (i+1);
 
         dt.Rows.Add(dr);
      }
 
      DataView dv = new DataView(dt);
      return dv;
   }
 
   void Page_Load(Object sender, EventArgs e) 
   {
 
      if (!IsPostBack) 
      {
         // Need to load this data only once.
         ItemsGrid.DataSource = CreateDataSource();
         ItemsGrid.DataBind();
      }
 
   }
 
   void Item_Created(Object sender, DataGridItemEventArgs e) 
   {
 
      if (e.Item.ItemType == ListItemType.Item ||
          e.Item.ItemType == ListItemType.AlternatingItem ||
          e.Item.ItemType == ListItemType.SelectedItem ||
          e.Item.ItemType == ListItemType.EditItem)

      {   
         Label1.Text += "<br />" + e.Item.ItemType.ToString() +
                        " - " + ((DataRowView)e.Item.DataItem).Row.ItemArray[1].ToString();
      }

      else

      {
         Label1.Text += "<br />" + e.Item.ItemType.ToString();
      }
 
   }
 
</script>
 
<head runat="server">
    <title>DataGridItem DataItem Example</title>
</head>
<body>
 
   <form id="form1" runat="server">

      <h3>DataGridItem DataItem Example</h3>
 
      <asp:DataGrid id="ItemsGrid" runat="server"
           BorderColor="black"
           BorderWidth="1"
           CellPadding="3"
           ShowFooter="true"
           OnItemCreated="Item_Created"
           AutoGenerateColumns="true">

         <HeaderStyle BackColor="#00aaaa">
         </HeaderStyle>

         <FooterStyle BackColor="#00aaaa">
         </FooterStyle>
   
      </asp:DataGrid>
 
      <br />
 
      <asp:Label id="Label1" 
           Text="Items in the DataGrid Control: <br />" 
           runat="server"/>
 
   </form>
 
</body>
</html>

Remarks

Use the DataItem property to specify or determine the properties of a data item represented by the DataGridItem object in the DataGrid control.

Note

This property applies only to data items in the DataGrid control. The ItemType property must be set to ListItemType.Item, ListItemType.AlternatingItem, ListItemType.SelectedItem, or ListItemType.EditItem.

Applies to

Product Versions
.NET Framework 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1

See also