VisualStyleElement.Button.PushButton.Default Property

Definition

Gets a visual style element that represents a default button.

C#
public static System.Windows.Forms.VisualStyles.VisualStyleElement Default { get; }

Property Value

A VisualStyleElement that represents a default button.

Examples

The following code example demonstrates how to create a VisualStyleRenderer with the VisualStyleElement returned by the Default property. To run this example, paste it into a Windows Form. Handle the form's Paint event and call the DrawVisualStyleElement_Button_PushButton5 method from the Paint event-handling method, passing e as PaintEventArgs.

C#
public void DrawVisualStyleElement_Button_PushButton5(PaintEventArgs e)
{
    if (VisualStyleRenderer.IsElementDefined(
        VisualStyleElement.Button.PushButton.Default))
    {
        VisualStyleRenderer renderer =
             new VisualStyleRenderer(VisualStyleElement.Button.PushButton.Default);
        Rectangle rectangle1 = new Rectangle(10, 50, 50, 50);
        renderer.DrawBackground(e.Graphics, rectangle1);
        e.Graphics.DrawString("VisualStyleElement.Button.PushButton.Default",
             this.Font, Brushes.Black, new Point(10, 10));
    }
    else
        e.Graphics.DrawString("This element is not defined in the current visual style.",
             this.Font, Brushes.Black, new Point(10, 10));
}

Remarks

You can use the VisualStyleElement returned by the Default property to create a VisualStyleRenderer.

Applies to

Product Versions
.NET Framework 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop 3.0, 3.1, 5, 6, 7, 8, 9, 10