Color.FromArgb(Byte, Byte, Byte, Byte) Method
Important
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Creates a new Color structure by using the specified sRGB
alpha channel and color channel values.
public:
static System::Windows::Media::Color FromArgb(System::Byte a, System::Byte r, System::Byte g, System::Byte b);
public static System.Windows.Media.Color FromArgb(byte a, byte r, byte g, byte b);
static member FromArgb : byte * byte * byte * byte -> System.Windows.Media.Color
Public Shared Function FromArgb (a As Byte, r As Byte, g As Byte, b As Byte) As Color
A Color structure with the specified values.
private Color FromArgbExample()
{
// Create a blue color using the FromArgb static method.
Color myArgbColor = new Color();
myArgbColor = Color.FromArgb(255, 0, 255, 0);
return myArgbColor;
}
Private Function FromArgbExample() As Color
' Create a blue color using the FromArgb static method.
Dim myArgbColor As New Color()
myArgbColor = Color.FromArgb(255, 0, 255, 0)
Return myArgbColor
End Function
The FromArgb method allows you to specify the alpha channel; the FromRgb method uses a default value of 255 for the alpha channel.
The alpha channel of a color determines the amount of transparency of the color. An alpha value of 255 indicates that the color is completely opaque, and a value of 0 indicates that the color is completely transparent.
Product | Versions |
---|---|
.NET Framework | 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
Windows Desktop | 3.0, 3.1, 5, 6, 7, 8, 9 |
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