XObject.NodeType Property
Definition
Important
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Gets the node type for this XObject.
public:
abstract property System::Xml::XmlNodeType NodeType { System::Xml::XmlNodeType get(); };
public abstract System.Xml.XmlNodeType NodeType { get; }
member this.NodeType : System.Xml.XmlNodeType
Public MustOverride ReadOnly Property NodeType As XmlNodeType
Property Value
The node type for this XObject.
Examples
The following example uses this method to retrieve the node type for a variety of nodes.
// Note that XNode uses XmlNodeType, which is in the System.Xml namespace.
XDocument xmlTree = new XDocument(
new XComment("a comment"),
new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),
new XElement("Root",
new XAttribute("Att", "attContent"),
new XElement("Child1",
new XCData("CDATA content")
),
new XElement("Child2",
new XText("Text content")
)
)
);
foreach (XNode node in xmlTree.DescendantNodes())
{
Console.WriteLine(node.NodeType);
if (node.NodeType == XmlNodeType.Element)
{
foreach (XAttribute att in ((XElement)node).Attributes())
Console.WriteLine(att.NodeType);
}
}
' Note that XNode uses XmlNodeType, which is in the System.Xml namespace.
Dim xmlTree As XDocument = _
<?xml version="1.0"?>
<!--a comment-->
<?xml-stylesheet type="text/xsl" href="hello.xsl"?>
<Root Att="attContent">
<Child1><![CDATA[CDATA content]]></Child1>
<Child2>Text content</Child2>
</Root>
For Each node As XNode In xmlTree.DescendantNodes
Console.WriteLine(node.NodeType.ToString())
If node.NodeType = XmlNodeType.Element Then
For Each att In DirectCast(node, XElement).Attributes
Console.WriteLine(att.NodeType.ToString())
Next
End If
Next
This example produces the following output:
Comment
ProcessingInstruction
Element
Attribute
Element
CDATA
Element
Text
Remarks
Because all classes that derive from XObject contain a NodeType property, you can write code that operates on collections of concrete subclass of XObject. Your code can then test for the node type of each node in the collection.