XmlArrayAttribute.ElementName Property

Reference

Definition

Namespace:: System.Xml.Serialization

Assemblies:: System.Xml.dll, System.Xml.XmlSerializer.dll

Assemblies:: netstandard.dll, System.Xml.XmlSerializer.dll

Assembly:: System.Xml.XmlSerializer.dll

Assembly:: System.Xml.dll

Assembly:: netstandard.dll

Source:: XmlArrayAttribute.cs

Source:: XmlArrayAttribute.cs

Source:: XmlArrayAttribute.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Gets or sets the XML element name given to the serialized array.

public:
 property System::String ^ ElementName { System::String ^ get(); void set(System::String ^ value); };

public string ElementName { get; set; }

member this.ElementName : string with get, set

Public Property ElementName As String

Property Value

String

The XML element name of the serialized array. The default is the name of the member to which the XmlArrayAttribute is assigned.

Examples

The following example serializes an instance of the Library class that contains a property named Books that returns an array of Book items. The example uses the ElementName property to specify that the array of XML elements should be named My_Books rather than Books.

#using <System.Xml.dll>
#using <System.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;
public ref class Book
{
public:
   String^ Title;
   String^ Author;
   String^ ISBN;
};

public ref class Library
{
private:
   array<Book^>^books;

public:

   [XmlArray(ElementName="My_Books")]
   property array<Book^>^ Books 
   {
      array<Book^>^ get()
      {
         return books;
      }

      void set( array<Book^>^value )
      {
         books = value;
      }
   }
};

int main()
{
   String^ filename = "ArrayExample.xml";
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Library::typeid );
   TextWriter^ t = gcnew StreamWriter( filename );
   XmlSerializerNamespaces^ ns = gcnew XmlSerializerNamespaces;
   ns->Add( "bk", "http://wwww.contoso.com" );
   Book^ b1 = gcnew Book;
   b1->Title = "MyBook Title";
   b1->Author = "An Author";
   b1->ISBN = "00000000";
   Book^ b2 = gcnew Book;
   b2->Title = "Another Title";
   b2->Author = "Another Author";
   b2->ISBN = "0000000";
   Library^ myLibrary = gcnew Library;
   array<Book^>^myBooks = {b1,b2};
   myLibrary->Books = myBooks;
   mySerializer->Serialize( t, myLibrary, ns );
   t->Close();
}

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Library
{
   private Book[] books;
   [XmlArray(ElementName="My_Books")]
   public Book[] Books
   {
      get{return books;}
      set{books = value;}
   }
}

public class Book
{
   public string Title;
   public string Author;
   public string ISBN;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.WriteBook("ArrayExample.xml");
   }

   public void WriteBook(string filename)
   {
      XmlSerializer mySerializer = new XmlSerializer(typeof(Library));
      TextWriter t = new StreamWriter(filename);
      XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
      ns.Add("bk", "http://wwww.contoso.com");

      Book b1 = new Book();
      b1.Title = "MyBook Title";
      b1.Author = "An Author";
      b1.ISBN = "00000000";

      Book b2 = new Book();
      b2.Title = "Another Title";
      b2.Author = "Another Author";
      b2.ISBN = "0000000";

      Library myLibrary = new Library();
      Book[] myBooks = {b1,b2};
      myLibrary.Books = myBooks;

      mySerializer.Serialize(t,myLibrary,ns);
      t.Close();
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Library
    Private myBooks() As Book
    
    <XmlArray(ElementName := "My_Books")> _
    Public Property Books() As Book()
        Get
            Return myBooks
        End Get
        Set
            myBooks = value
        End Set
    End Property
End Class
 
Public Class Book
    Public Title As String
    Public Author As String
    Public ISBN As String
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.WriteBook("ArrayExample.xml")
    End Sub
    
    
    Public Sub WriteBook(ByVal filename As String)
        Dim mySerializer As New XmlSerializer(GetType(Library))
        Dim t As New StreamWriter(filename)
        Dim ns As New XmlSerializerNamespaces()
        ns.Add("bk", "http://wwww.contoso.com")
        
        Dim b1 As New Book()
        b1.Title = "MyBook Title"
        b1.Author = "An Author"
        b1.ISBN = "00000000"
        
        Dim b2 As New Book()
        b2.Title = "Another Title"
        b2.Author = "Another Author"
        b2.ISBN = "0000000"
        
        Dim myLibrary As New Library()
        Dim myBooks() As Book =  {b1, b2}
        myLibrary.Books = myBooks
        
        mySerializer.Serialize(t, myLibrary, ns)
        t.Close()
    End Sub
End Class

Remarks

Specify an ElementName when you want the generated XML element name to differ from the member's identifier.

You can set the same ElementName value to more than one member as long as the generated XML document uses XML namespaces to distinguish between the identically named members. For more details about using namespaces and creating prefixed names in the XML document, see XmlSerializerNamespaces.

Applies to

Product	Versions
.NET	Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10
.NET Framework	1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard	2.0, 2.1
UWP	10.0

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