SyntaxFactory.AreEquivalent Método
Definición
Importante
Parte de la información hace referencia a la versión preliminar del producto, que puede haberse modificado sustancialmente antes de lanzar la versión definitiva. Microsoft no otorga ninguna garantía, explícita o implícita, con respecto a la información proporcionada aquí.
Sobrecargas
AreEquivalent(SyntaxTree, SyntaxTree, Boolean) |
Determina si dos árboles son los mismos, sin tener en cuenta las diferencias de trivia. |
AreEquivalent(SyntaxNode, SyntaxNode, Func<SyntaxKind,Boolean>) |
Determina si dos nodos de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia. |
AreEquivalent(SyntaxToken, SyntaxToken) |
Determina si dos tokens de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia. |
AreEquivalent(SyntaxTokenList, SyntaxTokenList) |
Determina si dos listas de tokens son las mismas, sin tener en cuenta las diferencias de trivia. |
AreEquivalent(SyntaxNode, SyntaxNode, Boolean) |
Determina si dos nodos de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia. |
AreEquivalent<TNode>(SeparatedSyntaxList<TNode>, SeparatedSyntaxList<TNode>, Func<SyntaxKind,Boolean>) |
Determina si dos listas de nodos de sintaxis son las mismas, sin tener en cuenta las diferencias de trivia. |
AreEquivalent<TNode>(SyntaxList<TNode>, SyntaxList<TNode>, Func<SyntaxKind,Boolean>) |
Determina si dos listas de nodos de sintaxis son las mismas, sin tener en cuenta las diferencias de trivia. |
AreEquivalent(SyntaxTree, SyntaxTree, Boolean)
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
Determina si dos árboles son los mismos, sin tener en cuenta las diferencias de trivia.
public:
static bool AreEquivalent(Microsoft::CodeAnalysis::SyntaxTree ^ oldTree, Microsoft::CodeAnalysis::SyntaxTree ^ newTree, bool topLevel);
public static bool AreEquivalent (Microsoft.CodeAnalysis.SyntaxTree oldTree, Microsoft.CodeAnalysis.SyntaxTree newTree, bool topLevel);
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxTree * Microsoft.CodeAnalysis.SyntaxTree * bool -> bool
Public Shared Function AreEquivalent (oldTree As SyntaxTree, newTree As SyntaxTree, topLevel As Boolean) As Boolean
Parámetros
- oldTree
- SyntaxTree
Árbol original.
- newTree
- SyntaxTree
Nuevo árbol.
- topLevel
- Boolean
True para omitir las diferencias de nodos dentro de cuerpos de métodos, operadores, constructores y descriptores de acceso, y inicializadores de campo y propiedad automática; de lo contrario, todos los nodos y tokens deben ser equivalentes.
Devoluciones
Se aplica a
AreEquivalent(SyntaxNode, SyntaxNode, Func<SyntaxKind,Boolean>)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
Determina si dos nodos de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia.
public static bool AreEquivalent (Microsoft.CodeAnalysis.SyntaxNode oldNode, Microsoft.CodeAnalysis.SyntaxNode newNode, Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind,bool> ignoreChildNode = default);
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxNode * Microsoft.CodeAnalysis.SyntaxNode * Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind, bool> -> bool
Public Shared Function AreEquivalent (oldNode As SyntaxNode, newNode As SyntaxNode, Optional ignoreChildNode As Func(Of SyntaxKind, Boolean) = Nothing) As Boolean
Parámetros
- oldNode
- SyntaxNode
Nodo anterior.
- newNode
- SyntaxNode
Nuevo nodo.
- ignoreChildNode
- Func<SyntaxKind,Boolean>
Si se ha especificado una llamada para cada nodo de sintaxis secundario (no token) que se visita durante la comparación. Devuelve true que el elemento secundario se visita de forma recursiva; de lo contrario, se ignora el elemento secundario y su subárbol.
Devoluciones
Se aplica a
AreEquivalent(SyntaxToken, SyntaxToken)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
Determina si dos tokens de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia.
public:
static bool AreEquivalent(Microsoft::CodeAnalysis::SyntaxToken oldToken, Microsoft::CodeAnalysis::SyntaxToken newToken);
public static bool AreEquivalent (Microsoft.CodeAnalysis.SyntaxToken oldToken, Microsoft.CodeAnalysis.SyntaxToken newToken);
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxToken * Microsoft.CodeAnalysis.SyntaxToken -> bool
Public Shared Function AreEquivalent (oldToken As SyntaxToken, newToken As SyntaxToken) As Boolean
Parámetros
- oldToken
- SyntaxToken
Token anterior.
- newToken
- SyntaxToken
Nuevo token.
Devoluciones
Se aplica a
AreEquivalent(SyntaxTokenList, SyntaxTokenList)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
Determina si dos listas de tokens son las mismas, sin tener en cuenta las diferencias de trivia.
public:
static bool AreEquivalent(Microsoft::CodeAnalysis::SyntaxTokenList oldList, Microsoft::CodeAnalysis::SyntaxTokenList newList);
public static bool AreEquivalent (Microsoft.CodeAnalysis.SyntaxTokenList oldList, Microsoft.CodeAnalysis.SyntaxTokenList newList);
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxTokenList * Microsoft.CodeAnalysis.SyntaxTokenList -> bool
Public Shared Function AreEquivalent (oldList As SyntaxTokenList, newList As SyntaxTokenList) As Boolean
Parámetros
- oldList
- SyntaxTokenList
Lista de tokens anterior.
- newList
- SyntaxTokenList
Nueva lista de tokens.
Devoluciones
Se aplica a
AreEquivalent(SyntaxNode, SyntaxNode, Boolean)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
Determina si dos nodos de sintaxis son los mismos, sin tener en cuenta las diferencias de trivia.
public:
static bool AreEquivalent(Microsoft::CodeAnalysis::SyntaxNode ^ oldNode, Microsoft::CodeAnalysis::SyntaxNode ^ newNode, bool topLevel);
public static bool AreEquivalent (Microsoft.CodeAnalysis.SyntaxNode oldNode, Microsoft.CodeAnalysis.SyntaxNode newNode, bool topLevel);
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxNode * Microsoft.CodeAnalysis.SyntaxNode * bool -> bool
Public Shared Function AreEquivalent (oldNode As SyntaxNode, newNode As SyntaxNode, topLevel As Boolean) As Boolean
Parámetros
- oldNode
- SyntaxNode
Nodo anterior.
- newNode
- SyntaxNode
Nuevo nodo.
- topLevel
- Boolean
True para omitir las diferencias de nodos dentro de cuerpos de métodos, operadores, constructores y descriptores de acceso, y inicializadores de campo y propiedad automática; de lo contrario, todos los nodos y tokens deben ser equivalentes.
Devoluciones
Se aplica a
AreEquivalent<TNode>(SeparatedSyntaxList<TNode>, SeparatedSyntaxList<TNode>, Func<SyntaxKind,Boolean>)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
Determina si dos listas de nodos de sintaxis son las mismas, sin tener en cuenta las diferencias de trivia.
public static bool AreEquivalent<TNode> (Microsoft.CodeAnalysis.SeparatedSyntaxList<TNode> oldList, Microsoft.CodeAnalysis.SeparatedSyntaxList<TNode> newList, Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind,bool> ignoreChildNode = default) where TNode : Microsoft.CodeAnalysis.SyntaxNode;
static member AreEquivalent : Microsoft.CodeAnalysis.SeparatedSyntaxList<'Node (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)> * Microsoft.CodeAnalysis.SeparatedSyntaxList<'Node (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)> * Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind, bool> -> bool (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)
Public Shared Function AreEquivalent(Of TNode As SyntaxNode) (oldList As SeparatedSyntaxList(Of TNode), newList As SeparatedSyntaxList(Of TNode), Optional ignoreChildNode As Func(Of SyntaxKind, Boolean) = Nothing) As Boolean
Parámetros de tipo
- TNode
Parámetros
- oldList
- SeparatedSyntaxList<TNode>
Lista antigua.
- newList
- SeparatedSyntaxList<TNode>
La nueva lista.
- ignoreChildNode
- Func<SyntaxKind,Boolean>
Si se ha especificado una llamada para cada nodo de sintaxis secundario (no token) que se visita durante la comparación. Devuelve true que el elemento secundario se visita de forma recursiva; de lo contrario, se ignora el elemento secundario y su subárbol.
Devoluciones
Se aplica a
AreEquivalent<TNode>(SyntaxList<TNode>, SyntaxList<TNode>, Func<SyntaxKind,Boolean>)
- Source:
- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
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- SyntaxFactory.vb
- Source:
- SyntaxFactory.vb
Determina si dos listas de nodos de sintaxis son las mismas, sin tener en cuenta las diferencias de trivia.
public static bool AreEquivalent<TNode> (Microsoft.CodeAnalysis.SyntaxList<TNode> oldList, Microsoft.CodeAnalysis.SyntaxList<TNode> newList, Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind,bool> ignoreChildNode = default) where TNode : Microsoft.CodeAnalysis.SyntaxNode;
static member AreEquivalent : Microsoft.CodeAnalysis.SyntaxList<'Node (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)> * Microsoft.CodeAnalysis.SyntaxList<'Node (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)> * Func<Microsoft.CodeAnalysis.VisualBasic.SyntaxKind, bool> -> bool (requires 'Node :> Microsoft.CodeAnalysis.SyntaxNode)
Public Shared Function AreEquivalent(Of TNode As SyntaxNode) (oldList As SyntaxList(Of TNode), newList As SyntaxList(Of TNode), Optional ignoreChildNode As Func(Of SyntaxKind, Boolean) = Nothing) As Boolean
Parámetros de tipo
- TNode
Parámetros
- oldList
- SyntaxList<TNode>
Lista antigua.
- newList
- SyntaxList<TNode>
La nueva lista.
- ignoreChildNode
- Func<SyntaxKind,Boolean>
Si se ha especificado una llamada para cada nodo de sintaxis secundario (no token) que se visita durante la comparación. Devuelve true que el elemento secundario se visita de forma recursiva; de lo contrario, se ignora el elemento secundario y su subárbol.