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Color.ToArgb Método

Definición

Obtiene el valor ARGB de 32 bits de esta estructura Color.

public:
 int ToArgb();
public int ToArgb ();
member this.ToArgb : unit -> int
Public Function ToArgb () As Integer

Devoluciones

Valor ARGB de 32 bits de este Color.

Ejemplos

El ejemplo de código siguiente está diseñado para su uso con Windows Forms y requiere PaintEventArgse, que es un parámetro del controlador de eventos Paint. El código realiza las siguientes acciones:

  • Recorre en iteración los elementos de enumeración KnownColor para buscar todos los colores conocidos que tienen un componente verde distinto de cero y un componente rojo de valor cero, y que no son colores del sistema.

  • Durante cada iteración, guarda el elemento KnownColor , si coincide con los criterios, en una matriz.

  • Usa un pincel para pintar rectángulos.

Cada uno de los rectángulos se pinta un KnownColor que coincide con los criterios indicados en la primera viñeta. También se muestran el nombre del KnownColor y sus valores de componente.

En este ejemplo se muestran determinados colores conocidos, los nombres de los colores y sus cuatro valores de componente. El método ToArgb se usa como paso preliminar para mostrar los valores del componente.

void ToArgbToStringExample1( PaintEventArgs^ e )
{
   Graphics^ g = e->Graphics;

   // Color structure used for temporary storage.
   Color someColor = Color::FromArgb( 0 );

   // Array to store KnownColor values that match the criteria.
   array<KnownColor>^colorMatches = gcnew array<KnownColor>(167);

   // Number of matches found.
   int count = 0;

   // Iterate through the KnownColor enums to find all corresponding colors
   // that have a nonzero green component and zero-value red component and
   // that are not system colors.
   for ( KnownColor enumValue = (KnownColor)0; enumValue <= KnownColor::YellowGreen; enumValue = enumValue + (KnownColor)1 )
   {
      someColor = Color::FromKnownColor( enumValue );
      if ( someColor.G != 0 && someColor.R == 0 &&  !someColor.IsSystemColor )
               colorMatches[ count++ ] = enumValue;
   }
   SolidBrush^ myBrush1 = gcnew SolidBrush( someColor );
   System::Drawing::Font^ myFont = gcnew System::Drawing::Font( "Arial",9 );
   int x = 40;
   int y = 40;

   // Iterate through the matches that were found and display each color that
   // corresponds with the enum value in the array. also display the name of
   // the KnownColor and the ARGB components.
   for ( int i = 0; i < count; i++ )
   {
      // Display the color.
      someColor = Color::FromKnownColor( colorMatches[ i ] );
      myBrush1->Color = someColor;
      g->FillRectangle( myBrush1, x, y, 50, 30 );

      // Display KnownColor name and the four component values. To display the
      // component values:  Use the ToArgb method to get the 32-bit ARGB value
      // of someColor, which was created from a KnownColor. Then create a
      // Color structure from the 32-bit ARGB value and set someColor equal to
      // this new Color structure. Then use the ToString method to convert it to
      // a string.
      g->DrawString( someColor.ToString(), myFont, Brushes::Black, (float)x + 55, (float)y );
      someColor = Color::FromArgb( someColor.ToArgb() );
      g->DrawString( someColor.ToString(), myFont, Brushes::Black, (float)x + 55, (float)y + 15 );
      y += 40;
   }
}
      public void ToArgbToStringExample1(PaintEventArgs e)
      {
          Graphics     g = e.Graphics;
                   
          // Color structure used for temporary storage.
          Color   someColor = Color.FromArgb(0);
                   
          // Array to store KnownColor values that match the criteria.
          KnownColor[]  colorMatches = new KnownColor[167];
          
          // Number of matches found.
          int  count = 0; 

          // Iterate through the KnownColor enums to find all corresponding colors
          // that have a nonzero green component and zero-value red component and
          // that are not system colors.
          for (KnownColor enumValue = 0;
              enumValue <= KnownColor.YellowGreen; enumValue++)
          {
              someColor = Color.FromKnownColor(enumValue);
              if (someColor.G != 0 && someColor.R == 0 && !someColor.IsSystemColor)
                  colorMatches[count++] = enumValue;
          }
          SolidBrush  myBrush1 = new SolidBrush(someColor);
          Font        myFont = new Font("Arial", 9);
          int         x = 40;
          int         y = 40;
                   
          // Iterate through the matches that were found and display each color that
          // corresponds with the enum value in the array. also display the name of
          // the KnownColor and the ARGB components.
          for (int i = 0; i < count; i++)
          {
                   
              // Display the color.
              someColor = Color.FromKnownColor(colorMatches[i]);
              myBrush1.Color = someColor;
              g.FillRectangle(myBrush1, x, y, 50, 30);
                   
              // Display KnownColor name and the four component values. To display the
              // component values:  Use the ToArgb method to get the 32-bit ARGB value
              // of someColor, which was created from a KnownColor. Then create a
              // Color structure from the 32-bit ARGB value and set someColor equal to
              // this new Color structure. Then use the ToString method to convert it to
              // a string.
              g.DrawString(someColor.ToString(), myFont, Brushes.Black, x + 55, y);
              someColor = Color.FromArgb(someColor.ToArgb());
              g.DrawString(someColor.ToString(), myFont, Brushes.Black, x + 55, y + 15);
              y += 40;
          }
      }
Public Sub ToArgbToStringExample1(ByVal e As PaintEventArgs)
    Dim g As Graphics = e.Graphics

    ' Color structure used for temporary storage.
    Dim someColor As Color = Color.FromArgb(0)

    ' Array to store KnownColor values that match the criteria.
    Dim colorMatches(167) As KnownColor

    ' Number of matches found.
    Dim count As Integer = 0

    ' Iterate through KnownColor enums to find all corresponding colors
    ' that have a non-zero green component and zero-valued red
    ' component and that are not system colors.
    Dim enumValue As KnownColor
    For enumValue = 0 To KnownColor.YellowGreen
        someColor = Color.FromKnownColor(enumValue)
        If someColor.G <> 0 And someColor.R = 0 And _
        Not someColor.IsSystemColor Then
            colorMatches(count) = enumValue
            count += 1
        End If
    Next enumValue
    Dim myBrush1 As New SolidBrush(someColor)
    Dim myFont As New Font("Arial", 9)
    Dim x As Integer = 40
    Dim y As Integer = 40

    ' Iterate through the matches found and display each color that
    ' corresponds with the enum value in the array. Also display the
    ' name of the KnownColor and the ARGB components.
    Dim i As Integer
    For i = 0 To count - 1

        ' Display the color.
        someColor = Color.FromKnownColor(colorMatches(i))
        myBrush1.Color = someColor
        g.FillRectangle(myBrush1, x, y, 50, 30)

        ' Display KnownColor name and four component values. To display
        ' component values:  Use the ToArgb method to get the 32-bit
        ' ARGB value of someColor (created from a KnownColor). Create
        ' a Color structure from the 32-bit ARGB value and set someColor
        ' equal to this new Color structure. Then use the ToString method
        ' to convert it to a string.
        g.DrawString(someColor.ToString(), myFont, Brushes.Black, _
        x + 55, y)
        someColor = Color.FromArgb(someColor.ToArgb())
        g.DrawString(someColor.ToString(), myFont, Brushes.Black, _
        x + 55, y + 15)
        y += 40
    Next i
End Sub

Comentarios

El orden de bytes del valor ARGB de 32 bits es AARRGGBB. El byte más significativo (MSB), representado por AA, es el valor del componente alfa. Los bytes segundo, tercero y cuarto, representados por RR, GG y BB, respectivamente, son los componentes de color rojo, verde y azul, respectivamente.

Se aplica a