Expression.MemberInit Método

Definición

Espacio de nombres:

System.Linq.Expressions

Ensamblado:

System.Linq.Expressions.dll

Representa una expresión que crea un nuevo objeto e inicializa una propiedad del objeto.

Sobrecargas

MemberInit(NewExpression, IEnumerable<MemberBinding>)	Representa una expresión que crea un nuevo objeto e inicializa una propiedad del objeto.
MemberInit(NewExpression, MemberBinding[])	Crea una interfaz MemberInitExpression.

MemberInit(NewExpression, IEnumerable<MemberBinding>)

Source:

MemberInitExpression.cs

Representa una expresión que crea un nuevo objeto e inicializa una propiedad del objeto.

public:
 static System::Linq::Expressions::MemberInitExpression ^ MemberInit(System::Linq::Expressions::NewExpression ^ newExpression, System::Collections::Generic::IEnumerable<System::Linq::Expressions::MemberBinding ^> ^ bindings);

public static System.Linq.Expressions.MemberInitExpression MemberInit (System.Linq.Expressions.NewExpression newExpression, System.Collections.Generic.IEnumerable<System.Linq.Expressions.MemberBinding> bindings);

static member MemberInit : System.Linq.Expressions.NewExpression * seq<System.Linq.Expressions.MemberBinding> -> System.Linq.Expressions.MemberInitExpression

Public Shared Function MemberInit (newExpression As NewExpression, bindings As IEnumerable(Of MemberBinding)) As MemberInitExpression

Parámetros

newExpression

NewExpression

NewExpression en el que se va a establecer la propiedad NewExpression.

bindings

IEnumerable<MemberBinding>

IEnumerable<T> que contiene los objetos MemberBinding que se van a usar para rellenar la colección de Bindings.

Devoluciones

MemberInitExpression

MemberInitExpression cuya propiedad NodeType es MemberInit y cuyas propiedades NewExpression y Bindings se establecen en los valores especificados.

Excepciones

ArgumentNullException

newExpression o bindings es null.

ArgumentException

La propiedad Member de un elemento de bindings no representa ningún miembro del tipo que newExpression.Type representa.

Ejemplos

En el ejemplo siguiente se muestra una expresión que crea un nuevo objeto e inicializa una propiedad del objeto .

// Add the following directive to your file:
// using System.Linq.Expressions;

class TestMemberInitClass
{
    public int sample { get; set; }
}

static void MemberInit()
{
    // This expression creates a new TestMemberInitClass object
    // and assigns 10 to its sample property.
    Expression testExpr = Expression.MemberInit(
        Expression.New(typeof(TestMemberInitClass)),
        new List<MemberBinding>() {
            Expression.Bind(typeof(TestMemberInitClass).GetMember("sample")[0], Expression.Constant(10))
        }
    );

    // The following statement first creates an expression tree,
    // then compiles it, and then runs it.
    var test = Expression.Lambda<Func<TestMemberInitClass>>(testExpr).Compile()();
    Console.WriteLine(test.sample);
}

// This code example produces the following output:
//
// 10

' Add the following directive to your file:
' Imports System.Linq.Expressions  

Class TestMemberInitClass
    Public Property Sample As Integer
End Class

Sub MemberInit()
    ' This expression creates a new TestMemberInitClass object
    ' and assigns 10 to its Sample property.
    Dim testExpr As Expression = Expression.MemberInit(
        Expression.[New](GetType(TestMemberInitClass)),
        New List(Of MemberBinding)() From {
            Expression.Bind(GetType(TestMemberInitClass).GetMember("Sample")(0), Expression.Constant(10))
        }
    )

    ' The following statement first creates an expression tree,
    ' then compiles it, and then runs it.
    Dim test = Expression.Lambda(Of Func(Of TestMemberInitClass))(testExpr).Compile()()
    Console.WriteLine(test.Sample)
End Sub

' This code example produces the following output:
'
' 10

Comentarios

La Type propiedad del resultante MemberInitExpression es igual a la Type propiedad de newExpression.

MemberInit(NewExpression, MemberBinding[])

Source:

MemberInitExpression.cs

Crea una interfaz MemberInitExpression.

public:
 static System::Linq::Expressions::MemberInitExpression ^ MemberInit(System::Linq::Expressions::NewExpression ^ newExpression, ... cli::array <System::Linq::Expressions::MemberBinding ^> ^ bindings);

public static System.Linq.Expressions.MemberInitExpression MemberInit (System.Linq.Expressions.NewExpression newExpression, params System.Linq.Expressions.MemberBinding[] bindings);

static member MemberInit : System.Linq.Expressions.NewExpression * System.Linq.Expressions.MemberBinding[] -> System.Linq.Expressions.MemberInitExpression

Public Shared Function MemberInit (newExpression As NewExpression, ParamArray bindings As MemberBinding()) As MemberInitExpression

Parámetros

newExpression

NewExpression

NewExpression en el que se va a establecer la propiedad NewExpression.

bindings

MemberBinding[]

Matriz de objetos MemberBinding que se va a usar para rellenar la colección de Bindings.

Devoluciones

MemberInitExpression

MemberInitExpression cuya propiedad NodeType es MemberInit y cuyas propiedades NewExpression y Bindings se establecen en los valores especificados.

Excepciones

ArgumentNullException

newExpression o bindings es null.

ArgumentException

La propiedad Member de un elemento de bindings no representa ningún miembro del tipo que newExpression.Type representa.

Ejemplos

En el ejemplo siguiente se muestra cómo usar el MemberInit(NewExpression, MemberBinding[]) método para crear un MemberInitExpression objeto que representa la inicialización de dos miembros de un nuevo objeto.

class Animal
{
    public string Species {get; set;}
    public int Age {get; set;}
}

public static void CreateMemberInitExpression()
{
    System.Linq.Expressions.NewExpression newAnimal =
        System.Linq.Expressions.Expression.New(typeof(Animal));

    System.Reflection.MemberInfo speciesMember =
        typeof(Animal).GetMember("Species")[0];
    System.Reflection.MemberInfo ageMember =
        typeof(Animal).GetMember("Age")[0];

    // Create a MemberBinding object for each member
    // that you want to initialize.
    System.Linq.Expressions.MemberBinding speciesMemberBinding =
        System.Linq.Expressions.Expression.Bind(
            speciesMember,
            System.Linq.Expressions.Expression.Constant("horse"));
    System.Linq.Expressions.MemberBinding ageMemberBinding =
        System.Linq.Expressions.Expression.Bind(
            ageMember,
            System.Linq.Expressions.Expression.Constant(12));

    // Create a MemberInitExpression that represents initializing
    // two members of the 'Animal' class.
    System.Linq.Expressions.MemberInitExpression memberInitExpression =
        System.Linq.Expressions.Expression.MemberInit(
            newAnimal,
            speciesMemberBinding,
            ageMemberBinding);

    Console.WriteLine(memberInitExpression.ToString());

    // This code produces the following output:
    //
    // new Animal() {Species = "horse", Age = 12}
}

Class Animal
    Public Species As String
    Public Age As Integer
End Class

Shared Sub CreateMemberInitExpression()
    Dim newAnimal As System.Linq.Expressions.NewExpression = _
        System.Linq.Expressions.Expression.[New](Type.GetType("ExpressionVB.MemberInitExample+Animal"))

    Dim speciesMember As System.Reflection.MemberInfo = _
        Type.GetType("ExpressionVB.MemberInitExample+Animal").GetMember("Species")(0)
    Dim ageMember As System.Reflection.MemberInfo = _
        Type.GetType("ExpressionVB.MemberInitExample+Animal").GetMember("Age")(0)

    ' Create a MemberBinding object for each member
    ' that you want to initialize.
    Dim speciesMemberBinding As System.Linq.Expressions.MemberBinding = _
        System.Linq.Expressions.Expression.Bind( _
            speciesMember, _
            System.Linq.Expressions.Expression.Constant("horse"))
    Dim ageMemberBinding As System.Linq.Expressions.MemberBinding = _
        System.Linq.Expressions.Expression.Bind( _
            ageMember, _
            System.Linq.Expressions.Expression.Constant(12))

    ' Create a MemberInitExpression that represents initializing
    ' two members of the 'Animal' class.
    Dim memberInitExpression As System.Linq.Expressions.MemberInitExpression = _
        System.Linq.Expressions.Expression.MemberInit( _
            newAnimal, _
            speciesMemberBinding, _
            ageMemberBinding)

    Console.WriteLine(memberInitExpression.ToString())

    ' This code produces the following output:
    '
    ' new Animal() {Species = "horse", Age = 12}
End Sub

Comentarios

La Type propiedad del resultante MemberInitExpression es igual a la Type propiedad de newExpression.