Tuple<T1,T2>.Item1 Propiedad

Definición

Espacio de nombres:

System

Ensamblado:

System.Runtime.dll

Source:

Tuple.cs

Obtiene el valor del primer componente del objeto Tuple<T1,T2> actual.

public:
 property T1 Item1 { T1 get(); };

public T1 Item1 { get; }

member this.Item1 : 'T1

Public ReadOnly Property Item1 As T1

Valor de propiedad

T1

Valor del primer componente del objeto Tuple<T1,T2> actual.

Ejemplos

En el ejemplo se muestra el uso de las Item1 propiedades y Item2 para definir un método que devuelve varios valores en forma de una tupla de 2.

using System;

public class Class1
{
   public static void Main()
   {
      int dividend, divisor;
      Tuple<int, int> result;
      
      dividend = 136945; divisor = 178;
      result = IntegerDivide(dividend, divisor);
      if (result != null)
         Console.WriteLine(@"{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2);
      else
         Console.WriteLine(@"{0} \ {1} = <Error>", dividend, divisor);
                        
      dividend = Int32.MaxValue; divisor = -2073;
      result = IntegerDivide(dividend, divisor);
      if (result != null)
         Console.WriteLine(@"{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2);
      else
         Console.WriteLine(@"{0} \ {1} = <Error>", dividend, divisor);
   }

   private static Tuple<int, int> IntegerDivide(int dividend, int divisor)
   {
      try {
         int remainder;
         int quotient = Math.DivRem(dividend, divisor, out remainder);
         return new Tuple<int, int>(quotient, remainder);
      }   
      catch (DivideByZeroException) {
         return null;
      }      
   }
}
// The example displays the following output:
//       136945 \ 178 = 769, remainder 63
//       2147483647 \ -2073 = -1035930, remainder 757

open System

let integerDivide (dividend: int) divisor =
    try
        let quotient, remainder = Math.DivRem(dividend, divisor)
        Tuple<int, int>(quotient, remainder)
    with :? DivideByZeroException ->
        Unchecked.defaultof<Tuple<int, int>>

[<EntryPoint>]
let main _ =
    let dividend = 136945 
    let divisor = 178
    let result = integerDivide dividend divisor
    if box result <> null then
        printfn $@"{dividend} \ {divisor} = {result.Item1}, remainder {result.Item2}" 
    else
        printfn $@"{dividend} \ {divisor} = <Error>"
                    
    let dividend = Int32.MaxValue 
    let divisor = -2073
    let result = integerDivide dividend divisor
    if box result <> null then
        printfn $@"{dividend} \ {divisor} = {result.Item1}, remainder {result.Item2}" 
    else
        printfn $@"{dividend} \ {divisor} = <Error>"
    0
// The example displays the following output:
//       136945 \ 178 = 769, remainder 63
//       2147483647 \ -2073 = -1035930, remainder 757

Module modMain
   Public Sub Main()
      Dim dividend, divisor As Integer
      Dim result As Tuple(Of Integer, Integer)
      
      dividend = 136945 : divisor = 178
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
                        
      dividend = Int32.MaxValue : divisor = -2073
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
   End Sub
   
   Private Function IntegerDivide(dividend As Integer, divisor As Integer) As Tuple(Of Integer, Integer)
      Try
         Dim remainder As Integer
         Dim quotient As Integer = Math.DivRem(dividend, divisor, remainder)
         Return New Tuple(Of Integer, Integer)(quotient, remainder)
      Catch e As DivideByZeroException
         Return Nothing
      End Try      
   End Function
End Module
' The example displays the following output:
'       136945 \ 178 = 769, remainder 63
'       2147483647 \ -2073 = -1035930, remainder 757

Comentarios

Puede determinar dinámicamente el tipo del Item1 componente de una de estas dos maneras:

• Llamando al GetType método en el valor devuelto por la Item1 propiedad .

• Recuperando el Type objeto que representa el Tuple<T1,T2> objeto y recuperando el primer elemento de la matriz devuelta por su Type.GetGenericArguments método.