MenuItem.Parent Property

Reference

Definition

Namespace:: System.Windows.Forms

Assembly:: System.Windows.Forms.dll

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Gets a value indicating the menu that contains this menu item.

public:
 property System::Windows::Forms::Menu ^ Parent { System::Windows::Forms::Menu ^ get(); };

[System.ComponentModel.Browsable(false)]
public System.Windows.Forms.Menu Parent { get; }

[<System.ComponentModel.Browsable(false)>]
member this.Parent : System.Windows.Forms.Menu

Public ReadOnly Property Parent As Menu

Property Value

A Menu that represents the menu that contains this menu item.

Attributes: BrowsableAttribute

Examples

In this example, you create a main menu and a top-level menu item, menuItem1 (File). You also create two menu items, menuItem2 (New) and menuItem3 (Open), and add them to the menu item list of menuItem1. Then you check to see if menuItem3 has got a parent menu, which is true, and display the information of this parent menu in message box. This example requires that you have created a Form named Form1.

public:
   void CreateMyMenuItems()
   {
      // Craete a main menu object.
      MainMenu^ mainMenu1 = gcnew MainMenu;

      // Create three top-level menu items.
      MenuItem^ menuItem1 = gcnew MenuItem( "&File" );
      MenuItem^ menuItem2 = gcnew MenuItem( "&New" );
      MenuItem^ menuItem3 = gcnew MenuItem( "&Open" );

      // Add menuItem1 to the main menu.
      mainMenu1->MenuItems->Add( menuItem1 );

      // Add menuItem2 and menuItem3 to menuItem1.
      menuItem1->MenuItems->Add( menuItem2 );
      menuItem1->MenuItems->Add( menuItem3 );

      // Check to see if menuItem3 has a parent menu.
      if ( menuItem3->Parent != nullptr )
            MessageBox::Show( String::Concat( menuItem3->Parent, "." ), "Parent Menu Information of menuItem3" );
      else
            MessageBox::Show( "No parent menu." );

      // Assign mainMenu1 to the form.
      this->Menu = mainMenu1;
   }

public void CreateMyMenuItems()
{
    // Craete a main menu object.
    MainMenu mainMenu1 = new MainMenu();

    // Create three top-level menu items.
    MenuItem menuItem1 = new MenuItem("&File");
    MenuItem menuItem2 = new MenuItem("&New");
    MenuItem menuItem3 = new MenuItem("&Open");

    // Add menuItem1 to the main menu.
    mainMenu1.MenuItems.Add(menuItem1);	

    // Add menuItem2 and menuItem3 to menuItem1.
    menuItem1.MenuItems.Add(menuItem2);
    menuItem1.MenuItems.Add(menuItem3);

    // Check to see if menuItem3 has a parent menu.
    if (menuItem3.Parent != null)
        MessageBox.Show(menuItem3.Parent.ToString()+
                ".", "Parent Menu Information of menuItem3"); 
    else
        MessageBox.Show("No parent menu."); 

    // Assign mainMenu1 to the form.
    this.Menu = mainMenu1;			
}

Public Sub CreateMyMenuItems()
    ' Craete a main menu object.
    Dim mainMenu1 As New MainMenu()

    ' Create three top-level menu items.
    Dim menuItem1 As New MenuItem("&File")
    Dim menuItem2 As New MenuItem("&New")
    Dim menuItem3 As New MenuItem("&Open")

    ' Add menuItem1 to the main menu.
    mainMenu1.MenuItems.Add(menuItem1)

    ' Add menuItem2 and menuItem3 to menuItem1.
    menuItem1.MenuItems.Add(menuItem2)
    menuItem1.MenuItems.Add(menuItem3)

    ' Check to see if menuItem3 has a parent menu.
    If (menuItem3.Parent IsNot Nothing) Then
        MessageBox.Show(menuItem3.Parent.ToString() + ".", "Parent Menu Information of menuItem3")
    Else
        MessageBox.Show("No parent menu.")
    End If
    ' Assign mainMenu1 to the form.
    Me.Menu = mainMenu1
End Sub

Remarks

You can use this property to obtain the Menu object for a submenu. You can cast the Menu object returned by this property to a MenuItem object to manipulate it.

Applies to

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